A gas has a pressure of 0.437 atm at 65.8 °C. What is its pressure at standard temperature?

I presume at constant volume


T1 = 65.8 + 273 = 388.8 K


T2 =%26gt; standard temperature = 273 K





0.437 / 388.8 = p2 / 273





p2 = 0.307 atm