Let Z be a standard normal random variable. Determine the value of C?

P (Z %26gt; C) = 0.8238





Round answer to at least two decimal points.

Let Z be a standard normal random variable. Determine the value of C?
Z ~ N(0,1)





P(Z %26gt; C) = 0.8238


1 - P(Z %26lt; C) = 0.8238


P(Z %26lt; C) = 0.1762


C = -0.93


(C can be either looked up in statistical tables or solved with spreadsheet programs such as Microsoft Excel.)

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