can anybody help me.
I need c++ functions to calculate the mean and standard deviation of some numbers?
void mean_stddeviation(float d[ ],float%26amp; mean, float%26amp; std_dev)
{
int l = length(d);
mean =0;
for (int i =0; i%26lt;l;i++)
mean +=d(i);
mean /= l;
for (i=0;i%26lt;l;i++)
std_dev += (d(i) - mean )*(d(i)-mean);
std_dev /= l;
std_dev = sqrt(std_dev);
}
Tuesday, July 14, 2009
How do i remove the standard cd player in the corsa c i have got the security keys but still cannot remove?
Check that you have the right keys - they are u shaped and it does take a bit of tugging to get it out
How do i remove the standard cd player in the corsa c i have got the security keys but still cannot remove?
do the same as neil said above, but on some models it's possible to push the unit from behind to help it on it's way out if u can get ur hand up
Reply:Push the keys into the holes each side of the unit as far as they will go, then push the ends of the keys apart (so the points push inward against the sides of the unit), and gently but firmly pull the unit out.
It may require some jiggling to get it free.
Reply:Just requires a bit more muscle....quite a bugger to remove.
Reply:rip it out lol
you will need to go to kw it fin it be £50
Reply:you dont do it yourself!!!!send it in because you will damage the hidden pins that the standard cd player accomodates close to the back of the cage...
Reply:Firstly have you removed the little grub screws (the pins will not fit the holes if not)
Second is it the single din unit (old shape Corsa) or is it the new double din size.
If double din you need to make sure that the pins (keys as you call them) are not bent. They need to go into the holes dead parallel or they will not release the clips. I have seen these really out of shape brand new out of the packet from halfords so you may well need to reshape them quite a bit to get them to fit properly.
If this does not work don't try to force it out, find a friendly car radio or carphone fitter and ask him to remove it
How do i remove the standard cd player in the corsa c i have got the security keys but still cannot remove?
do the same as neil said above, but on some models it's possible to push the unit from behind to help it on it's way out if u can get ur hand up
Reply:Push the keys into the holes each side of the unit as far as they will go, then push the ends of the keys apart (so the points push inward against the sides of the unit), and gently but firmly pull the unit out.
It may require some jiggling to get it free.
Reply:Just requires a bit more muscle....quite a bugger to remove.
Reply:rip it out lol
you will need to go to kw it fin it be £50
Reply:you dont do it yourself!!!!send it in because you will damage the hidden pins that the standard cd player accomodates close to the back of the cage...
Reply:Firstly have you removed the little grub screws (the pins will not fit the holes if not)
Second is it the single din unit (old shape Corsa) or is it the new double din size.
If double din you need to make sure that the pins (keys as you call them) are not bent. They need to go into the holes dead parallel or they will not release the clips. I have seen these really out of shape brand new out of the packet from halfords so you may well need to reshape them quite a bit to get them to fit properly.
If this does not work don't try to force it out, find a friendly car radio or carphone fitter and ask him to remove it
I want to view tenth standard icse result please help name C.M. PONNANNA ROLL NO. - T/1085/047?
www.cisce.indiaresult.com
A gas has a pressure of 0.292 atm at 46.2 ° C. What is its pressure at standard temperature?
0.164 atm
P1/T1 = P2/T2.
Standard temp = 273,15 = T2
T1 = 273,15+ 46.2
P1 = 0.292;
A gas has a pressure of 0.292 atm at 46.2 ° C. What is its pressure at standard temperature?
I have no idea...
P1/T1 = P2/T2.
Standard temp = 273,15 = T2
T1 = 273,15+ 46.2
P1 = 0.292;
A gas has a pressure of 0.292 atm at 46.2 ° C. What is its pressure at standard temperature?
I have no idea...
A gas has a pressure of 0.437 atm at 65.8 °C. What is its pressure at standard temperature?
I presume at constant volume
T1 = 65.8 + 273 = 388.8 K
T2 =%26gt; standard temperature = 273 K
0.437 / 388.8 = p2 / 273
p2 = 0.307 atm
T1 = 65.8 + 273 = 388.8 K
T2 =%26gt; standard temperature = 273 K
0.437 / 388.8 = p2 / 273
p2 = 0.307 atm
A gas has a pressure of 699.0 mmHg at 40.0°C. What is the temperature at standard pressure?
Please use significant figures and show work.
A gas has a pressure of 699.0 mmHg at 40.0°C. What is the temperature at standard pressure?
Gay Lussac's Law. As volume isn't mentioned, I'll assume it's constant.
P1 x T2 = P2 x T1
699mmHg x T2 = 760mmHg x 313K (40°C)
T2 = 760 x 313 ÷ 699
Final Pressure = 237,880 ÷ 699 = 340.3K = 67.3°C.
Reply:Sorry about that but a slight error in my answer. I put 'Final Pressure' instead of Temperature. Report It
Reply:P1= 699.0 mm Hg= 93 kPa
T1= 40.0+273=313 K
P2=101.3 (standart pressure)
T2= X
93 divided by 313= .30X
101.3 divided by .30
temperature= 337 kelvin= 64 degrees celcius
i think this is right...
Reply:699.0 mm Hg / 313 K = 760 mm Hg / x
A gas has a pressure of 699.0 mmHg at 40.0°C. What is the temperature at standard pressure?
Gay Lussac's Law. As volume isn't mentioned, I'll assume it's constant.
P1 x T2 = P2 x T1
699mmHg x T2 = 760mmHg x 313K (40°C)
T2 = 760 x 313 ÷ 699
Final Pressure = 237,880 ÷ 699 = 340.3K = 67.3°C.
Reply:Sorry about that but a slight error in my answer. I put 'Final Pressure' instead of Temperature. Report It
Reply:P1= 699.0 mm Hg= 93 kPa
T1= 40.0+273=313 K
P2=101.3 (standart pressure)
T2= X
93 divided by 313= .30X
101.3 divided by .30
temperature= 337 kelvin= 64 degrees celcius
i think this is right...
Reply:699.0 mm Hg / 313 K = 760 mm Hg / x
What is the standard rate of tax deducted from bank savings a/c in US?
I have in mind 15%, but I am not sure.
In the UK it is 20% standard rate and 40% higher rate. (The unending wars we get involved in, do not come cheap).
What is the standard rate of tax deducted from bank savings a/c in US?
Unless you have failed to pay your Federal taxes in a timely fashion, and hence subject to "backup withholding," banks may not deduct any money for the payment of taxes. However, they are required to report your earnings to the Treasury and you are obligated to file a tax return and pay taxes on it. You may ask them to voluntarily withhold at the standard rate used for "backup withholding," which is, I believe 15%.
Reply:In the US there is no tax rate fixed to an saving account. The bank will issue a 1099 INT which will show how much interest you have earn during the year (same with dividends and capital gain). These will be reported to the IRS. You then have to file your own tax return that will include all your revenue, earnings and any deduction (and wages withholdings). Based on your earnings (including those received as interest on your saving account) you will have to pay a certain tax rate. Tax rate goes up to 40% for federal to which you have to add State tax. However because of deductions and different rate for capital gain(15% only for LT gain) or AMT, few people actually pay the max, but usually end up with a blended rate.
Talk to you tax accountant.
Good luck...we still have to finance a war and they kept on cutting taxes...what a country.
Reply:Unless you are subject to backup withholding, the bank doesn't deduct anything from your savings for taxes
Reply:no deduction. you're requred to report all your interest income on your tax forms.
wallflower
In the UK it is 20% standard rate and 40% higher rate. (The unending wars we get involved in, do not come cheap).
What is the standard rate of tax deducted from bank savings a/c in US?
Unless you have failed to pay your Federal taxes in a timely fashion, and hence subject to "backup withholding," banks may not deduct any money for the payment of taxes. However, they are required to report your earnings to the Treasury and you are obligated to file a tax return and pay taxes on it. You may ask them to voluntarily withhold at the standard rate used for "backup withholding," which is, I believe 15%.
Reply:In the US there is no tax rate fixed to an saving account. The bank will issue a 1099 INT which will show how much interest you have earn during the year (same with dividends and capital gain). These will be reported to the IRS. You then have to file your own tax return that will include all your revenue, earnings and any deduction (and wages withholdings). Based on your earnings (including those received as interest on your saving account) you will have to pay a certain tax rate. Tax rate goes up to 40% for federal to which you have to add State tax. However because of deductions and different rate for capital gain(15% only for LT gain) or AMT, few people actually pay the max, but usually end up with a blended rate.
Talk to you tax accountant.
Good luck...we still have to finance a war and they kept on cutting taxes...what a country.
Reply:Unless you are subject to backup withholding, the bank doesn't deduct anything from your savings for taxes
Reply:no deduction. you're requred to report all your interest income on your tax forms.
wallflower
Whats easier to play, drop c or drop d tuning, or standard..?
Drop D is easier because it only requires one finger to play power chofds.
Give a program in C to print the mean and standard deviation of a set of values?
I don't remember what needs to be included for the function "sqrt", but this function looks right to me...didn't try it, but should only need a few changes if any.
double float stddev (float* set, int set_length)
{
int i;
float mean = 0.0;
double float sigma = 0.0;
for (i = 0; i %26lt; set_length; i++)
{
mean += (set[i] / (float) set_length);
}
for (i = 0; i %26lt; set_length; i++)
{
float diff = set[i] - mean;
sigma += (diff * diff);
}
sigma = (sigma / (float) set_length);
return sqrt(sigma);
}
double float stddev (float* set, int set_length)
{
int i;
float mean = 0.0;
double float sigma = 0.0;
for (i = 0; i %26lt; set_length; i++)
{
mean += (set[i] / (float) set_length);
}
for (i = 0; i %26lt; set_length; i++)
{
float diff = set[i] - mean;
sigma += (diff * diff);
}
sigma = (sigma / (float) set_length);
return sqrt(sigma);
}
Is old s.s.c course equivalent to 11 th standard?
now a days we don't have ssc corse ..we have polytechnic couses for 11th and 12th...its better to join 11th instead of polytechnic..
What conclusion you can draw from the value of the standard deviation obtained in part c?
Standard deviation is defined as the amount of spread between the values given. In your case, the standard deviation obtained from part C %26lt;whereever it may be%26gt; determines how far apart the values in part c are. If it is big, then the values may be very far apart %26lt;like 5 and 789%26gt;. If it's small, then they may be a bit closer than that %26lt;like 15 and 23%26gt;.
-//-//-
hollyhock
-//-//-
hollyhock
Write 2.5x-0.3/3 =1/6y in standard form. Identify A, B, C. I know the answer is 2.5x - 5y = 3, but how?
2.5x - 0.3/3 = (1/6)y
mutiply each by 6
15x - .6 = y
15x - y = .6 to get rid of the fraction, multiply each by 5
75x - 5y = 3
Is the original problem this:
(2.5x - .3)/3 = (1/6)y
then the answer is 25x - 5y = 3
2.5x is not correct in the answer, if it's 2.5 in the original problem. Please check both. If your book has it that way both times, the book has an error.
Write 2.5x-0.3/3 =1/6y in standard form. Identify A, B, C. I know the answer is 2.5x - 5y = 3, but how?
It's Friday. Don't worry about it till Sunday.
Reply:Maybe they have saturday school.
mutiply each by 6
15x - .6 = y
15x - y = .6 to get rid of the fraction, multiply each by 5
75x - 5y = 3
Is the original problem this:
(2.5x - .3)/3 = (1/6)y
then the answer is 25x - 5y = 3
2.5x is not correct in the answer, if it's 2.5 in the original problem. Please check both. If your book has it that way both times, the book has an error.
Write 2.5x-0.3/3 =1/6y in standard form. Identify A, B, C. I know the answer is 2.5x - 5y = 3, but how?
It's Friday. Don't worry about it till Sunday.
Reply:Maybe they have saturday school.
Which of the following gas molecules has the greatest standard molar entropy at 25°C?
C2H2
CH2CH2
CH3CH3
All would have the same entropy
Which of the following gas molecules has the greatest standard molar entropy at 25°C?
As maolecular mass increases the molar entropy decreases is the usual RULE of thumb.
Therefore C2H2 would have greatest standard molar entropy!
CH2CH2
CH3CH3
All would have the same entropy
Which of the following gas molecules has the greatest standard molar entropy at 25°C?
As maolecular mass increases the molar entropy decreases is the usual RULE of thumb.
Therefore C2H2 would have greatest standard molar entropy!
What jobs are available for those who possess standard first aid/cpr, level c in toronto?
is there a website
What jobs are available for those who possess standard first aid/cpr, level c in toronto?
u can try the toronto sun's website which is newspaper .........torontosun.ca
What jobs are available for those who possess standard first aid/cpr, level c in toronto?
u can try the toronto sun's website which is newspaper .........torontosun.ca
Let Z be a standard normal random variable. Determine the value of C?
P (Z %26gt; C) = 0.8238
Round answer to at least two decimal points.
Let Z be a standard normal random variable. Determine the value of C?
Z ~ N(0,1)
P(Z %26gt; C) = 0.8238
1 - P(Z %26lt; C) = 0.8238
P(Z %26lt; C) = 0.1762
C = -0.93
(C can be either looked up in statistical tables or solved with spreadsheet programs such as Microsoft Excel.)
cabbage
Round answer to at least two decimal points.
Let Z be a standard normal random variable. Determine the value of C?
Z ~ N(0,1)
P(Z %26gt; C) = 0.8238
1 - P(Z %26lt; C) = 0.8238
P(Z %26lt; C) = 0.1762
C = -0.93
(C can be either looked up in statistical tables or solved with spreadsheet programs such as Microsoft Excel.)
cabbage
As ice melts at Standard pressure, its temperature remains at 0 degrees C. until it has melted. Its P.E._____?
*P.E.= Potential Energy
A) remains the same
B) increases
C) Decreases
As ice melts at Standard pressure, its temperature remains at 0 degrees C. until it has melted. Its P.E._____?
B increases. is correct.
Potential energy is that energy which causes a change in state [ie from solid to liquid to gas] without causing a change in temperature.
As you heat water to boiling point and it reaches 100C, you have to continue putting heat into it to boil it.
BUT you will never get it to go above 100C however much heat you put into it.
This 'lost' heat is potential energy and is going to change the state, not raise the temperature.
Just remember that as things change state, as they go up in temperature or go from solid to liquid to gas they GAIN potential energy.
As they go down, from gas to liquid to solid they lose potential energy.
It is this energy that keeps them in the state they are in.
Reply:ok so i just learned this at school, so im hoping this is right, but im not completely sure...
it may be: C
like i said im not truly sure if this is right or not, just a guess
Reply:You have never had a girlfriend, have you?
A) remains the same
B) increases
C) Decreases
As ice melts at Standard pressure, its temperature remains at 0 degrees C. until it has melted. Its P.E._____?
B increases. is correct.
Potential energy is that energy which causes a change in state [ie from solid to liquid to gas] without causing a change in temperature.
As you heat water to boiling point and it reaches 100C, you have to continue putting heat into it to boil it.
BUT you will never get it to go above 100C however much heat you put into it.
This 'lost' heat is potential energy and is going to change the state, not raise the temperature.
Just remember that as things change state, as they go up in temperature or go from solid to liquid to gas they GAIN potential energy.
As they go down, from gas to liquid to solid they lose potential energy.
It is this energy that keeps them in the state they are in.
Reply:ok so i just learned this at school, so im hoping this is right, but im not completely sure...
it may be: C
like i said im not truly sure if this is right or not, just a guess
Reply:You have never had a girlfriend, have you?
How do u convert a equation into standard form like (Ax+By=c)? do these problems y=-4x+8-1/2x-4y=6?
other problem -4y+4x+5=6
first answer gets best answer
How do u convert a equation into standard form like (Ax+By=c)? do these problems y=-4x+8-1/2x-4y=6?
y=-4x+8-1
4x+y=7
2x-4y=6 (already done)
-4y+4x+5=6
4x-4y=1
first answer gets best answer
How do u convert a equation into standard form like (Ax+By=c)? do these problems y=-4x+8-1/2x-4y=6?
y=-4x+8-1
4x+y=7
2x-4y=6 (already done)
-4y+4x+5=6
4x-4y=1
How hard is it to convert a C-6 Automatic Tranni into a 4-speed Standard?
How much would this cost roughly? i have a 1977 Ford F-150 with a 351M and a C-6 automatic Tranni.
How hard is it to convert a C-6 Automatic Tranni into a 4-speed Standard?
#1) You want to remove the Automatic, purchase a Manual and install the Manual in your truck?
or #2)are you asking how to convert a Automatic Transmission to a Manual transmission?
The first #1 is Possible but a lot of work.
new Flywheel, clutch, pressure plate ...install pedals, hydraulic throw out bearing and cylinders, etc, etc.
If you have a donor truck/car from a salvage it will be much easier.
The Second i#2 is not plausible and won't happen.
Yours: Grumpy
Reply:Remove tailshaft, starter motor, speedo drive, kickdown, Vacuum modulator line(if fitted), cooling lines, crossmember, autotrans(with convertor), flexplate, brake pedal/pedal assembly. Install pilot bush(in back of crankshaft), flywheel and (longer)bolts, clutch %26amp; pressure plate, bellhousing, starter motor, gearbox, crossmember, shifter %26amp;/or linkages,speedo drive, tailshaft, pedal assembly(with clutch pedal), clutch master, clutch slave and line. Not hard but there is a bit more to it. Your cost should be no more than parts (gearbox, shifter, clutch, pressure plate, flywheel, pedal assembly , a few bolts here and there and oil). I live in Australia so I'm not sure what parts are worth where you live. PARTS for this truck are HEAVY so don't be a hero. Good jacks are a must to hold up a big 4 speed. An experienced mechanic working in the driveway at home could easily do this job in a day. You don't say if the truck is column or floor auto. If column, you can remove the shift stick or replace the whole column with a floorshift unit.
Reply:A couple hundred of bucks if you know what you are doing. Maybe as much as $500 if you pay someone to do it. Note, don't do this unless you know how to do it already. It's not rocket science. But, it's not trivial either.
Reply:It's a pain in the butt. That C-6 is the best you can have. If you want to change your truck...find a 3/4ton Dana 60 with 3.50 gears and you will see a major improvement....unless you are currently running a 3.50 or 3.73 gear set.
How hard is it to convert a C-6 Automatic Tranni into a 4-speed Standard?
#1) You want to remove the Automatic, purchase a Manual and install the Manual in your truck?
or #2)are you asking how to convert a Automatic Transmission to a Manual transmission?
The first #1 is Possible but a lot of work.
new Flywheel, clutch, pressure plate ...install pedals, hydraulic throw out bearing and cylinders, etc, etc.
If you have a donor truck/car from a salvage it will be much easier.
The Second i#2 is not plausible and won't happen.
Yours: Grumpy
Reply:Remove tailshaft, starter motor, speedo drive, kickdown, Vacuum modulator line(if fitted), cooling lines, crossmember, autotrans(with convertor), flexplate, brake pedal/pedal assembly. Install pilot bush(in back of crankshaft), flywheel and (longer)bolts, clutch %26amp; pressure plate, bellhousing, starter motor, gearbox, crossmember, shifter %26amp;/or linkages,speedo drive, tailshaft, pedal assembly(with clutch pedal), clutch master, clutch slave and line. Not hard but there is a bit more to it. Your cost should be no more than parts (gearbox, shifter, clutch, pressure plate, flywheel, pedal assembly , a few bolts here and there and oil). I live in Australia so I'm not sure what parts are worth where you live. PARTS for this truck are HEAVY so don't be a hero. Good jacks are a must to hold up a big 4 speed. An experienced mechanic working in the driveway at home could easily do this job in a day. You don't say if the truck is column or floor auto. If column, you can remove the shift stick or replace the whole column with a floorshift unit.
Reply:A couple hundred of bucks if you know what you are doing. Maybe as much as $500 if you pay someone to do it. Note, don't do this unless you know how to do it already. It's not rocket science. But, it's not trivial either.
Reply:It's a pain in the butt. That C-6 is the best you can have. If you want to change your truck...find a 3/4ton Dana 60 with 3.50 gears and you will see a major improvement....unless you are currently running a 3.50 or 3.73 gear set.
Derive the Quadratic equation from standard form (ax^2+bx+c=0) must show work?
ax^2 + bx + c = 0
so a ( x^2 + b/a x ) + c = 0,
remember that if (x+y)^2 = x^2 + 2xy + y^2
so, if you assume 'b/a x' as middle term for (x+y)^2,
we can write a ( x^2 + b/ax + (b/2a)^2 - (b/2a)^2 ) + c = 0.
be careful that x^2 + b/ax+ (b/2a)^2 mean (x+ b/2a)^2.
so, rewrite that a { (x+b/2a)^2 - (b/2a)^2 } + c = 0.
so, a( x+b/2a)^2 - b/4a +c = 0.
generally, we assume h= b/2a and k= c- b/4a
in this way, we can transform ax^2 + bx + c into a(x+h)^2+k.
again, ax^2+bx+c = 0,.
ax^2 + bx = -c
x^2 + b/ax = -c/a
x^2 + b/ax + (b/2a)^2 = (b/2a)^2 - c/a
(x+ b/2a) ^2 = b^2/4a^2 - 4ac/4a^2
x+b/2a = + or - sqrt { (b^2-4ac)/2a }
so x = [-b +or- sqrt { (b^2-4ac) } ] / 2a.
this is the solution to all quadratic equation.
note b^2 is always %26gt; 4ac.
if b^2%26lt; 4ac, then we get complex numbers of roots.
Derive the Quadratic equation from standard form (ax^2+bx+c=0) must show work?
I guess you didn't look around very much as even Wikipedia gives the derivation.
Reply:http://en.wikipedia.org/wiki/Quadratic_e...
phlox
so a ( x^2 + b/a x ) + c = 0,
remember that if (x+y)^2 = x^2 + 2xy + y^2
so, if you assume 'b/a x' as middle term for (x+y)^2,
we can write a ( x^2 + b/ax + (b/2a)^2 - (b/2a)^2 ) + c = 0.
be careful that x^2 + b/ax+ (b/2a)^2 mean (x+ b/2a)^2.
so, rewrite that a { (x+b/2a)^2 - (b/2a)^2 } + c = 0.
so, a( x+b/2a)^2 - b/4a +c = 0.
generally, we assume h= b/2a and k= c- b/4a
in this way, we can transform ax^2 + bx + c into a(x+h)^2+k.
again, ax^2+bx+c = 0,.
ax^2 + bx = -c
x^2 + b/ax = -c/a
x^2 + b/ax + (b/2a)^2 = (b/2a)^2 - c/a
(x+ b/2a) ^2 = b^2/4a^2 - 4ac/4a^2
x+b/2a = + or - sqrt { (b^2-4ac)/2a }
so x = [-b +or- sqrt { (b^2-4ac) } ] / 2a.
this is the solution to all quadratic equation.
note b^2 is always %26gt; 4ac.
if b^2%26lt; 4ac, then we get complex numbers of roots.
Derive the Quadratic equation from standard form (ax^2+bx+c=0) must show work?
I guess you didn't look around very much as even Wikipedia gives the derivation.
Reply:http://en.wikipedia.org/wiki/Quadratic_e...
phlox
Standard tube size for class c artillery shells?
Please be specific
Standard tube size for class c artillery shells?
http://www.groupsrv.com/hobby/about18709...
bottom
Standard tube size for class c artillery shells?
http://www.groupsrv.com/hobby/about18709...
bottom
I want admission for my daughter into grade 3 (have T.C frm dubai) at Tampines. Standard reply "No vacancy".
Looks like you'll have to find another place for her to attend. Or bribe somebody.
I want admission for my daughter into grade 3 (have T.C frm dubai) at Tampines. Standard reply "No vacancy".
You posted in USA! not India.
Reply:aaaah-haaaaa!
I want admission for my daughter into grade 3 (have T.C frm dubai) at Tampines. Standard reply "No vacancy".
You posted in USA! not India.
Reply:aaaah-haaaaa!
What is the standard free-energy change G° at 25°C for the following reaction?
C(graphite) + 2 Cl2(g) CCl4(l)
2.Calculate the value of the thermodynamic equilibrium constant K.
What is the standard free-energy change G° at 25°C for the following reaction?
Lancenigo di Villorba (TV), Italy
The reaction involved is
C(Graphite) + 2 Cl2(g) ---%26gt; CCl4(l)
Its own STANDARD GIBB-FREE ENERGY's CHANGE follows
DeltaG° = (G°f,CCl4) - (G°f,C + 2 * G°f,Cl2) =
= (-203,344) - (0.0 + 2 * 0.0) = -203,344 J/mol
Instead I use the FORMATION's GIBB-FREE ENERGY for Carbon Tetrachloride, I assumed NIHIL the other ones since they refer to MOST STABLE ALLOTROPIC STATES of Chemical Elements.
The "Isothermal van't Hoff Equation"
DeltaG = DeltaG° + R * T * SUM[nu,i * LN(a,i)]
may be rearranged at the Equilibrium Conditions, e.g. where it is DeltaG = 0 and SUM[nu,i * LN(a,i)] = LN(Keq)
so it is
Keq = EXP(0 - DeltaG° / (R * T)) =
= EXP(0 - (-203,344) / (8.3 * 298.16)) = 4.8E+35
I hope this could be clear.
2.Calculate the value of the thermodynamic equilibrium constant K.
What is the standard free-energy change G° at 25°C for the following reaction?
Lancenigo di Villorba (TV), Italy
The reaction involved is
C(Graphite) + 2 Cl2(g) ---%26gt; CCl4(l)
Its own STANDARD GIBB-FREE ENERGY's CHANGE follows
DeltaG° = (G°f,CCl4) - (G°f,C + 2 * G°f,Cl2) =
= (-203,344) - (0.0 + 2 * 0.0) = -203,344 J/mol
Instead I use the FORMATION's GIBB-FREE ENERGY for Carbon Tetrachloride, I assumed NIHIL the other ones since they refer to MOST STABLE ALLOTROPIC STATES of Chemical Elements.
The "Isothermal van't Hoff Equation"
DeltaG = DeltaG° + R * T * SUM[nu,i * LN(a,i)]
may be rearranged at the Equilibrium Conditions, e.g. where it is DeltaG = 0 and SUM[nu,i * LN(a,i)] = LN(Keq)
so it is
Keq = EXP(0 - DeltaG° / (R * T)) =
= EXP(0 - (-203,344) / (8.3 * 298.16)) = 4.8E+35
I hope this could be clear.
What is the standard way to set up your R/C transmitter?
I am new at r/c flying. i bought a flight simulator and want to learn the right way. my motor glider works on a rudder and elevator on the tail. do you set up the plane and transmitter to
have the elevator and rudder on the right stick and the throttle
only on the left. and then if you get a plane with ailerons you put that on the left stick or the right. also do planes come with rudders and ailerons. my point is do i learn to go left/right with the right stick and save ailerons,barrel rolls, for the left stick.
or is the whole thing a matter of preference.
What is the standard way to set up your R/C transmitter?
Mode 2 in the USA . . dominate roll axis (rudder or ailerons) on right stick . . throttle on left stick.
FMS tutorial
http://www.tti-us.com/sim/FMSop.html#men...
Reply:each person has there own way but I put the rudder and elevator on one stick and the ailerons and throttle on the other. It's all about how you control the plane and whats comfotable to you.
verbena
have the elevator and rudder on the right stick and the throttle
only on the left. and then if you get a plane with ailerons you put that on the left stick or the right. also do planes come with rudders and ailerons. my point is do i learn to go left/right with the right stick and save ailerons,barrel rolls, for the left stick.
or is the whole thing a matter of preference.
What is the standard way to set up your R/C transmitter?
Mode 2 in the USA . . dominate roll axis (rudder or ailerons) on right stick . . throttle on left stick.
FMS tutorial
http://www.tti-us.com/sim/FMSop.html#men...
Reply:each person has there own way but I put the rudder and elevator on one stick and the ailerons and throttle on the other. It's all about how you control the plane and whats comfotable to you.
verbena
How likely is the Coop Bank to close your a/c if you write sending standard letter asking for charges back?
100%.
The Co-Op bank sent me a letter closing my account as I went overdrawn by a few pound,twice.
How likely is the Coop Bank to close your a/c if you write sending standard letter asking for charges back?
there is no right but what kind of ur account is important %26amp; the terms of ur account
Reply:I got back charges from them just by a phone call on the internet banking so it's not all bad.
Reply:well seeing as they market themselves as the ethical bank i would hope not
The Co-Op bank sent me a letter closing my account as I went overdrawn by a few pound,twice.
How likely is the Coop Bank to close your a/c if you write sending standard letter asking for charges back?
there is no right but what kind of ur account is important %26amp; the terms of ur account
Reply:I got back charges from them just by a phone call on the internet banking so it's not all bad.
Reply:well seeing as they market themselves as the ethical bank i would hope not
Can any1 give me standard procedure for calling java method from "c++" using vc++?
basically it invovles invoking JVM....
i tried but got errors !
i tried as follows =%26gt;
created .java ,.class,.h files using javac,javah cmds.
opened vc++ =%26gt; win32 appl'n %26gt; c++ file as source
program is @ sun site JNI specification book ! invocation api's chapter...simple hello world program...
then i set paths of library at file jvm.lib.
set the preprocessor path to jni.h means C:\j2sdk1.4.2_05\include
and run ....
gives many errors linking error like
Linking...
LIBCD.lib(wincrt0.obj) : error LNK2001: unresolved external symbol _WinMain@16
Debug/ltry.exe : fatal error LNK1120: 1 unresolved externals
Error executing link.exe.
ltry.exe - 2 error(s), 0 warning(s)
sometimes gives error C:\ltry\tr.cpp(18) : warning C4129: 'j' : unrecognized character escape sequence
in code @
options[0].optionString="-Djava.class....
can any1 tell me valid procedure ?
do u hav anyother gud book for invocation api's?
Thanks Amit
Can any1 give me standard procedure for calling java method from "c++" using vc++?
I dont know what the probelm is but it does work when i refer
the docs.
But the procedure will br something like
1. Create a JVM Instance
2. Create an object of the Java Class
3. Call the Method.
The Names will be something like
Java_ClassName_MethodName( Para List );
i tried but got errors !
i tried as follows =%26gt;
created .java ,.class,.h files using javac,javah cmds.
opened vc++ =%26gt; win32 appl'n %26gt; c++ file as source
program is @ sun site JNI specification book ! invocation api's chapter...simple hello world program...
then i set paths of library at file jvm.lib.
set the preprocessor path to jni.h means C:\j2sdk1.4.2_05\include
and run ....
gives many errors linking error like
Linking...
LIBCD.lib(wincrt0.obj) : error LNK2001: unresolved external symbol _WinMain@16
Debug/ltry.exe : fatal error LNK1120: 1 unresolved externals
Error executing link.exe.
ltry.exe - 2 error(s), 0 warning(s)
sometimes gives error C:\ltry\tr.cpp(18) : warning C4129: 'j' : unrecognized character escape sequence
in code @
options[0].optionString="-Djava.class....
can any1 tell me valid procedure ?
do u hav anyother gud book for invocation api's?
Thanks Amit
Can any1 give me standard procedure for calling java method from "c++" using vc++?
I dont know what the probelm is but it does work when i refer
the docs.
But the procedure will br something like
1. Create a JVM Instance
2. Create an object of the Java Class
3. Call the Method.
The Names will be something like
Java_ClassName_MethodName( Para List );
32=-27x to the 2nd power +12x . Write the following equation in standard form and determine a b c?
a=
b=
c=
32=-27x to the 2nd power +12x . Write the following equation in standard form and determine a b c?
Standerd form of a quadractic equation looks like this ax^2+bx+c=0 so to do that you would subtract 32 on both sides and you would get -27x^2+12x-32=0 however you would want to write it like this 27x^2-12x-32=0 the first coeffeiciant would be a = 27 the second coefficiant would be b= -12 and finally the constant c= -32 as a quadratic equation is ax^2+bx+c=0
Reply:Thats nearly correct unknown (above)
Unfortunately you made a mistake
When you changed all the signs you missed the sign on the 32, it should be positive.
a = 27
b = -12
c = 32
And nada J must be on drugs
Reply:oki
32 = (-27X)^2 + 12X
32 = 729(x^2) + 12x
729(x^2) + 12x - 32 = 0
so i donno if u mean that
a = 729
b = 12
c = -32
i hope i was able to help
good luck!
b=
c=
32=-27x to the 2nd power +12x . Write the following equation in standard form and determine a b c?
Standerd form of a quadractic equation looks like this ax^2+bx+c=0 so to do that you would subtract 32 on both sides and you would get -27x^2+12x-32=0 however you would want to write it like this 27x^2-12x-32=0 the first coeffeiciant would be a = 27 the second coefficiant would be b= -12 and finally the constant c= -32 as a quadratic equation is ax^2+bx+c=0
Reply:Thats nearly correct unknown (above)
Unfortunately you made a mistake
When you changed all the signs you missed the sign on the 32, it should be positive.
a = 27
b = -12
c = 32
And nada J must be on drugs
Reply:oki
32 = (-27X)^2 + 12X
32 = 729(x^2) + 12x
729(x^2) + 12x - 32 = 0
so i donno if u mean that
a = 729
b = 12
c = -32
i hope i was able to help
good luck!
Test grade? my score is 43. The ave 62(B-/C+) Min=0 Max=110 standard deviation= 23.95? DO u think its a low C?
You are within one standard deviation of the average, so if it's graded on a curve, you may survive.
Test grade? my score is 43. The ave 62(B-/C+) Min=0 Max=110 standard deviation= 23.95? DO u think its a low C?
Where I go, the 60's would be a D!
Reply:You're hanging in the D range bro.
snapdragon2
Test grade? my score is 43. The ave 62(B-/C+) Min=0 Max=110 standard deviation= 23.95? DO u think its a low C?
Where I go, the 60's would be a D!
Reply:You're hanging in the D range bro.
snapdragon2
If i mailed a letter to b.c canada from tx at standard mailing rate how long does it take?
i sent it last thursday night would it be there by now
If i mailed a letter to b.c canada from tx at standard mailing rate how long does it take?
It will take about 5-7 days.
If i mailed a letter to b.c canada from tx at standard mailing rate how long does it take?
It will take about 5-7 days.
Write a C program to print Fibonacci series using arrays, Write a C program to determine the mean and standard
plse help me to understand these question and how to write a code in c programming
Write a C program to print Fibonacci series using arrays, Write a C program to determine the mean and standard
Here is a little sample that is directly lifted from the "MyCPlus" website. This will prompt for a number and then give the Fibonacci numbers.
#include %26lt;stdio.h%26gt;
int main(void) {
int n; /* The number of fibonacci numbers we will print */
int i; /* The index of fibonacci number to be printed next */
int current; /* The value of the (i)th fibonacci number */
int next; /* The value of the (i+1)th fibonacci number */
int twoaway; /* The value of the (i+2)th fibonacci number */
printf("How many Fibonacci numbers do you want to compute? ");
scanf("%d", %26amp;n);
if (n%26lt;=0)
printf("The number should be positive.\n");
else {
printf("\n\n\tI \t Fibonacci(I) \n\t=====================\n");
next = current = 1;
for (i=1; i%26lt;=n; i++) {
printf("\t%d \t %d\n", i, current);
twoaway = current+next;
current = next;
next = twoaway;
}
}
}
Write a C program to print Fibonacci series using arrays, Write a C program to determine the mean and standard
Here is a little sample that is directly lifted from the "MyCPlus" website. This will prompt for a number and then give the Fibonacci numbers.
#include %26lt;stdio.h%26gt;
int main(void) {
int n; /* The number of fibonacci numbers we will print */
int i; /* The index of fibonacci number to be printed next */
int current; /* The value of the (i)th fibonacci number */
int next; /* The value of the (i+1)th fibonacci number */
int twoaway; /* The value of the (i+2)th fibonacci number */
printf("How many Fibonacci numbers do you want to compute? ");
scanf("%d", %26amp;n);
if (n%26lt;=0)
printf("The number should be positive.\n");
else {
printf("\n\n\tI \t Fibonacci(I) \n\t=====================\n");
next = current = 1;
for (i=1; i%26lt;=n; i++) {
printf("\t%d \t %d\n", i, current);
twoaway = current+next;
current = next;
next = twoaway;
}
}
}
How do I write 2c^2-c^2+5c as a standard polynomial?
Combine the c^2 terms, i.e., 2c^2 - c^2 = (2-1)c^2 = c^2. That gives c^2 + 5c (or if you want to highlight the constant term, c^2 + 5c + 0).
What does VGCSE (grades A*-C) or SQA Intermediate 2 standard means?
In school grade
What does VGCSE (grades A*-C) or SQA Intermediate 2 standard means?
Intermediate 2 is an educational qualification in Scotland on the Scottish Qualifications Authority (SQA) Scottish Qualifications Certificate (SQC) achievement ladder similar to Credit Level at Standard Grades; it is the next step after Intermediate 1.
VGCSE stands for Vocational Certificate of Secondary Education. VGCSE is an extension to the GCSE system used in the UK which offers students the opportunity of applied knowledge courses, especially in ICT.
avender
What does VGCSE (grades A*-C) or SQA Intermediate 2 standard means?
Intermediate 2 is an educational qualification in Scotland on the Scottish Qualifications Authority (SQA) Scottish Qualifications Certificate (SQC) achievement ladder similar to Credit Level at Standard Grades; it is the next step after Intermediate 1.
VGCSE stands for Vocational Certificate of Secondary Education. VGCSE is an extension to the GCSE system used in the UK which offers students the opportunity of applied knowledge courses, especially in ICT.
avender
Which of the following processes has a negative standard free energy change at 25°C?
a) CH4 (g) + 2O2 (g) → CO2 (g) + 2H2O (g)
b) 2Na (s) + 2H2O (l) → 2NaOH (aq) + H2 (g)
c) 2H2O (l) → 2H2 (g) + O2 (g)
d) Both a and b
Which of the following processes has a negative standard free energy change at 25°C?
a definitely, b i'm not so sure. Rule of thumb, if a chemical reaction releases heat, it is a negative free energy change. So, when you add sodium to water, does it heat up? i believe it may but i don't know for sure
i can tell you it is definitely a positive free energy change to split up water into oxygen and hydrogen.
so, either a or d
Reply:Option (d ) is correct.
(a) is a highly exothermic reaction.
(b)Here ΔH is (-) %26amp; ΔS is (+) =%26gt; ΔG is "negative".
b) 2Na (s) + 2H2O (l) → 2NaOH (aq) + H2 (g)
c) 2H2O (l) → 2H2 (g) + O2 (g)
d) Both a and b
Which of the following processes has a negative standard free energy change at 25°C?
a definitely, b i'm not so sure. Rule of thumb, if a chemical reaction releases heat, it is a negative free energy change. So, when you add sodium to water, does it heat up? i believe it may but i don't know for sure
i can tell you it is definitely a positive free energy change to split up water into oxygen and hydrogen.
so, either a or d
Reply:Option (d ) is correct.
(a) is a highly exothermic reaction.
(b)Here ΔH is (-) %26amp; ΔS is (+) =%26gt; ΔG is "negative".
Please write a C++ code for average and standard deviation and route mean square?
Please help me
Please write a C++ code for average and standard deviation and route mean square?
Do your homework yourself
Reply:Yes, do the homework yourself. One thing that might be helful is to use math class in c++.
do this
#include %26lt;math.h%26gt;
sometimes its
#include %26lt;math%26gt;
go to this website to see what functions you will need. like srt and pow
http://www.cplusplus.com/ref/cmath/
ex: Take a sqrt of 5
#include %26lt;math.h%26gt;
#include %26lt;iostream.h%26gt;
void main(){
cout %26lt;%26lt; "Square Roo of 5:" %26lt;%26lt; sqrt(5) %26lt;%26lt; endl;
}
Thats it, I just helped you a ton. The rest is up to you. You really should do the hw yourself or ask a teacher.
Good Luck
Please write a C++ code for average and standard deviation and route mean square?
Do your homework yourself
Reply:Yes, do the homework yourself. One thing that might be helful is to use math class in c++.
do this
#include %26lt;math.h%26gt;
sometimes its
#include %26lt;math%26gt;
go to this website to see what functions you will need. like srt and pow
http://www.cplusplus.com/ref/cmath/
ex: Take a sqrt of 5
#include %26lt;math.h%26gt;
#include %26lt;iostream.h%26gt;
void main(){
cout %26lt;%26lt; "Square Roo of 5:" %26lt;%26lt; sqrt(5) %26lt;%26lt; endl;
}
Thats it, I just helped you a ton. The rest is up to you. You really should do the hw yourself or ask a teacher.
Good Luck
I Want To Programme(in C Language) of Data Encryption Standard & 3(Tripall)Data Encryption Standard?
Data Encryption Software Package
Dsoft infotech offers data protection software. Card size CD for locking ... developed by IBM became the Data Encryption Standard (DES) and was issued by the ...http://www.dsoftinfotech.com/encryption....
I Want To Programme(in C Language) of Data Encryption Standard %26amp; 3(Tripall)Data Encryption Standard?
You don't "programme" computers - you program them.
Rawlyn.
Dsoft infotech offers data protection software. Card size CD for locking ... developed by IBM became the Data Encryption Standard (DES) and was issued by the ...http://www.dsoftinfotech.com/encryption....
I Want To Programme(in C Language) of Data Encryption Standard %26amp; 3(Tripall)Data Encryption Standard?
You don't "programme" computers - you program them.
Rawlyn.
Is it possible to define new functions with the same names as standard library functions in 'C' language?
Yes. That's called "overloading."
Is it possible to define new functions with the same names as standard library functions in 'C' language?
Yes it is possible. However, the reason the library exists is to stnadardize many of the common elements required for writing code, so that people were not re-inventing the wheel each time they wrote a program in C.
That said, several string input functions--such as gets() and scanf()--are the source of many buffer overflow attacks by hackers. So it might be a good idea to re-write the headers, and use your own custom library of more secure functions. That way you will have more robust and secure code in your programs.
Reply:Sure. Just don't use the standard library header directly.
Reply:No, it is not possible.
Not if you link your program with standard library and use standard headers.
Overloading exists only in C++ and allows to define new functions with the same names, but different parameter types. Overloading does not apply to C language and standard C library functions.
You can't redefine, for example, function printf() or atoi(); If you make C function with the same name and parameter types, the program won't link because of naming conflicts.
In C++ program (but not C) you can make function with the same name as library function - like atoi() for example, but it has to have different parameter types, and it won't replace the original library function.
violet
Is it possible to define new functions with the same names as standard library functions in 'C' language?
Yes it is possible. However, the reason the library exists is to stnadardize many of the common elements required for writing code, so that people were not re-inventing the wheel each time they wrote a program in C.
That said, several string input functions--such as gets() and scanf()--are the source of many buffer overflow attacks by hackers. So it might be a good idea to re-write the headers, and use your own custom library of more secure functions. That way you will have more robust and secure code in your programs.
Reply:Sure. Just don't use the standard library header directly.
Reply:No, it is not possible.
Not if you link your program with standard library and use standard headers.
Overloading exists only in C++ and allows to define new functions with the same names, but different parameter types. Overloading does not apply to C language and standard C library functions.
You can't redefine, for example, function printf() or atoi(); If you make C function with the same name and parameter types, the program won't link because of naming conflicts.
In C++ program (but not C) you can make function with the same name as library function - like atoi() for example, but it has to have different parameter types, and it won't replace the original library function.
violet
Determine the equation of the line. Express the final equation in standard form Ax+By+C=0 HOw do i do this?
horizontal line through (2,-4)
the vertical line through (2,-9)
*Plz don't just give me the answer, cuz thats not going to help me understand how you got the answer...can you explain how you get each step?*
Determine the equation of the line. Express the final equation in standard form Ax+By+C=0 HOw do i do this?
in a horizontal line, all values of x will produce the same y
therefore, the coefficient of x should be zero. a horizontal line also has no slope which means that the coefficient of x has to be zero. In this case, A has to equal 0.
Also, because we know the horizontal line goes through -4, we know that -C/B = -4. When you rearrange the equation to solve for y, it looks like By = -C and then y = -C/B and since y always equals -4, -C/B = -4.
On the vertical line, its a little harder, you will have an infinite slope, which means you can't really have a full equation. It will look more like 1x + 0y - 2 = 0
Reply:Horizontal lines are in the form y = a number. In the point (2, -4) you can see that y = 4
Vertical lines are in the form x = a number. In the point (2, -9) you can see that x = 2
In standard form they would be
0x+y-4 = 0
x+0y-2 = 0
the vertical line through (2,-9)
*Plz don't just give me the answer, cuz thats not going to help me understand how you got the answer...can you explain how you get each step?*
Determine the equation of the line. Express the final equation in standard form Ax+By+C=0 HOw do i do this?
in a horizontal line, all values of x will produce the same y
therefore, the coefficient of x should be zero. a horizontal line also has no slope which means that the coefficient of x has to be zero. In this case, A has to equal 0.
Also, because we know the horizontal line goes through -4, we know that -C/B = -4. When you rearrange the equation to solve for y, it looks like By = -C and then y = -C/B and since y always equals -4, -C/B = -4.
On the vertical line, its a little harder, you will have an infinite slope, which means you can't really have a full equation. It will look more like 1x + 0y - 2 = 0
Reply:Horizontal lines are in the form y = a number. In the point (2, -4) you can see that y = 4
Vertical lines are in the form x = a number. In the point (2, -9) you can see that x = 2
In standard form they would be
0x+y-4 = 0
x+0y-2 = 0
How do i change y-intercept form (y=mx+b) into standard form (Ax+By=C)?
Transpose the "mx" term to the left side to get:
-mx + y = b
---------------------------------
The details:
Usually they don't allow negatives in front, so just multiply everything by -1 if m is negative.
mx - y = -b
Also, if you have any fractional coefficients, they need to be gotten rid of by multiplication of the GCD of the fractions (but you probably won't ever have to deal with problems with more than one fraction).
--------------------------------------
Example: y = 3x +6 becomes
-3x + y = 6 and then
3x - y = -6
Example: y = (2/3)x -3
-(2/3)x + y = -3
(2/3)x - y = 3
2x -3y = 9 %26lt;--------------Multiply every term by 3
How do i change y-intercept form (y=mx+b) into standard form (Ax+By=C)?
I might be wrong but wouldn't you change it to the pont slope form which would be y - y1=M(x-x1) ??
Reply:this formula: -a/b+c/b
example:y=2(5)+4
2=a
5=b
4=c
-2/5+4/5
just plug in the numbers than simplify
hope this helped some, coverting things are pretty tricky
Reply:Just transpose mx to the left hand side to get
y -mx = b
this is in the form Ax + By = C
where A =-m
B = 1 and
C =b
Reply:Subtract the b and add subtract the y to isolate the b on one side. After that, adjust the equation so that it has Ax before the By. The c is b
-mx + y = b
---------------------------------
The details:
Usually they don't allow negatives in front, so just multiply everything by -1 if m is negative.
mx - y = -b
Also, if you have any fractional coefficients, they need to be gotten rid of by multiplication of the GCD of the fractions (but you probably won't ever have to deal with problems with more than one fraction).
--------------------------------------
Example: y = 3x +6 becomes
-3x + y = 6 and then
3x - y = -6
Example: y = (2/3)x -3
-(2/3)x + y = -3
(2/3)x - y = 3
2x -3y = 9 %26lt;--------------Multiply every term by 3
How do i change y-intercept form (y=mx+b) into standard form (Ax+By=C)?
I might be wrong but wouldn't you change it to the pont slope form which would be y - y1=M(x-x1) ??
Reply:this formula: -a/b+c/b
example:y=2(5)+4
2=a
5=b
4=c
-2/5+4/5
just plug in the numbers than simplify
hope this helped some, coverting things are pretty tricky
Reply:Just transpose mx to the left hand side to get
y -mx = b
this is in the form Ax + By = C
where A =-m
B = 1 and
C =b
Reply:Subtract the b and add subtract the y to isolate the b on one side. After that, adjust the equation so that it has Ax before the By. The c is b
A 50 mL sample of gas is collected at 37 C. What is its volume at standard temperature, 0.0 C?
22.4 liters is the standard.
C program to find the standard deviation. i need program also explain the process?
pls soon reply
C program to find the standard deviation. i need program also explain the process?
#include%26lt;stdio.h%26gt;
#include%26lt;conio.h%26gt;
#include%26lt;math.h%26gt;
void main()
{
int n,i,j; /*initialising the variables */
double max[100],sum=0,variance,mean=0;
printf('enter the size of array \n");
scanf("%d",%26amp;n); /*reading the no of elements we needed */
printf("enter the elements of array:\n");
for(i=0;i%26lt;n;i++) /*reading the elements to array max[ ]*/
scanf("%lf",%26amp;max[i]);
i=0; /* initializing the variable to zero.This variable can be used as outer loop variable*/
printf ("\n");
/*loop written to calculate the summation which we can see in the formula (refer to formula of mean)*/
for(j=0;j%26lt;n;j++)
{
sum+=max[i];
i++;
}
mean=sum/i; /* calculating the mean value */
printf("sum of the elements:");
printf("%lf",sum);
printf("mean of the elements:");
printf("%lf",mean);
i=0; /*resetting the variable to zero %26amp; here also it works as outer loop variable in calculating the variance*/
sum=0; /* reset the sum to zero*/
for(j=0;j%26lt;n;j++) /* calculating summation in variance formula (refer to variance formula )*/
{
max[i]=pow((max[i]-mean),2);
sum+=max[i];
i++;
}
variance=sum/(i-1); /* calculating variance*/
printf("standard deviation:"); /* printing the standard deviation as it is the square root of
printf("%lf",sqrt(variance)); variance*/
}
peony
C program to find the standard deviation. i need program also explain the process?
#include%26lt;stdio.h%26gt;
#include%26lt;conio.h%26gt;
#include%26lt;math.h%26gt;
void main()
{
int n,i,j; /*initialising the variables */
double max[100],sum=0,variance,mean=0;
printf('enter the size of array \n");
scanf("%d",%26amp;n); /*reading the no of elements we needed */
printf("enter the elements of array:\n");
for(i=0;i%26lt;n;i++) /*reading the elements to array max[ ]*/
scanf("%lf",%26amp;max[i]);
i=0; /* initializing the variable to zero.This variable can be used as outer loop variable*/
printf ("\n");
/*loop written to calculate the summation which we can see in the formula (refer to formula of mean)*/
for(j=0;j%26lt;n;j++)
{
sum+=max[i];
i++;
}
mean=sum/i; /* calculating the mean value */
printf("sum of the elements:");
printf("%lf",sum);
printf("mean of the elements:");
printf("%lf",mean);
i=0; /*resetting the variable to zero %26amp; here also it works as outer loop variable in calculating the variance*/
sum=0; /* reset the sum to zero*/
for(j=0;j%26lt;n;j++) /* calculating summation in variance formula (refer to variance formula )*/
{
max[i]=pow((max[i]-mean),2);
sum+=max[i];
i++;
}
variance=sum/(i-1); /* calculating variance*/
printf("standard deviation:"); /* printing the standard deviation as it is the square root of
printf("%lf",sqrt(variance)); variance*/
}
peony
Will a sports vectra sport kit fit on a standard vectra? 2002 model c shape?
na
Will a sports vectra sport kit fit on a standard vectra? 2002 model c shape?
It will if each car is a model c..
Will a sports vectra sport kit fit on a standard vectra? 2002 model c shape?
It will if each car is a model c..
How do you change y=4x+(-6) into standard form(ax+by=c)?
please tell me how, thanks
How do you change y=4x+(-6) into standard form(ax+by=c)?
(4)x + (-1)y=6
a = 4
b = -1
c = 6
i think...
Reply:subtract -4x from both side... and that is it. Answer: -4x+y= -6
Reply:the "c" is the number not being multiplied by x or y in your case its -6 so leave that on the right side and move the 4x to the left side by subtracting it from both sides. it should look like what you want
How do you change y=4x+(-6) into standard form(ax+by=c)?
(4)x + (-1)y=6
a = 4
b = -1
c = 6
i think...
Reply:subtract -4x from both side... and that is it. Answer: -4x+y= -6
Reply:the "c" is the number not being multiplied by x or y in your case its -6 so leave that on the right side and move the 4x to the left side by subtracting it from both sides. it should look like what you want
How do you convert y=3x-6 into standard form (Ax+by=c)?
y=3x-6
subtract 3x from both sides
-3x + y = -6
= ]
How do you convert y=3x-6 into standard form (Ax+by=c)?
y=3x-6 into standard form (Ax+by=c)?
Just move things around!
y - 3x = -6 or
-3x + y = -6. Done.
Reply:A is just the coefficient for x, which means the number beside it. B is the coefficient for y, and C is the constant, the number without a variable(a letter that stands for a number unkown for the time being)
(Ax+By=C)
Now, just take 3x to the other side, and you have it in standard form, Ax+By=C.
Remember to switch the signs of 3x, because it was subracted on both sides.
Reply:y=3x-6
3x - y = 6
You can move terms from one side of the equals sign to the other as long as you change its sign.
Reply:Just move some stuff around. Subtract y and add 6 and you get:
3x - y = 6
So A = 3, B = -1, and C = 6
Reply:In this case you have by = ax - c .... where b = 1; a= 3 and c = 6 to leave it in standard form, you solve for c.
so, you bring c to the other side of the equation (positive) and vice versa with b (now negative) and you get c = ax - by or in other words C = Ax + (-by) where c=6; b=1 and a = 3
final answer:
3x + (-y) = 6
Hope it helped! :)
Reply:first move x and y to right side (with change sign)
y-3x=-6
put first x then y
-3x + y = -6
Ax+By=C
So
A=-3,B=1 ,and C=-6
subtract 3x from both sides
-3x + y = -6
= ]
How do you convert y=3x-6 into standard form (Ax+by=c)?
y=3x-6 into standard form (Ax+by=c)?
Just move things around!
y - 3x = -6 or
-3x + y = -6. Done.
Reply:A is just the coefficient for x, which means the number beside it. B is the coefficient for y, and C is the constant, the number without a variable(a letter that stands for a number unkown for the time being)
(Ax+By=C)
Now, just take 3x to the other side, and you have it in standard form, Ax+By=C.
Remember to switch the signs of 3x, because it was subracted on both sides.
Reply:y=3x-6
3x - y = 6
You can move terms from one side of the equals sign to the other as long as you change its sign.
Reply:Just move some stuff around. Subtract y and add 6 and you get:
3x - y = 6
So A = 3, B = -1, and C = 6
Reply:In this case you have by = ax - c .... where b = 1; a= 3 and c = 6 to leave it in standard form, you solve for c.
so, you bring c to the other side of the equation (positive) and vice versa with b (now negative) and you get c = ax - by or in other words C = Ax + (-by) where c=6; b=1 and a = 3
final answer:
3x + (-y) = 6
Hope it helped! :)
Reply:first move x and y to right side (with change sign)
y-3x=-6
put first x then y
-3x + y = -6
Ax+By=C
So
A=-3,B=1 ,and C=-6
Write the equatin of the line in standard form (Ax+By=C) that passes through points: (-5,10) and (-4,-2).?
Any line with the equation y=mx+c has a slope of m and a y-intercept of c.
You know that when x=-5, y=10, so if you plug these into your y=mx+c formula:
10=-5m+c
You also know that when x=-4 y=-2, so if you plug these into your y=mx+c formula:
-2=-4m+c
You can now solve these as simultaneous equations:
Let equation 1 be 10=-5m+c
Let equation 2 be -2=-4m+c
Take equation 2 from equation 1:
12=-m
so m=-12
Plug this value into equation 1:
10=(-5*-12)+c
10=60+c
so c=-50
Therefore your y=mx+c equation is:
y=-12x-50
Rewriting for the form Ax+By=c:
12x+y=-50
Write the equatin of the line in standard form (Ax+By=C) that passes through points: (-5,10) and (-4,-2).?
first get the slope:
(-2 - 10) / (-4 - (-5) ) = -12/1 = -12
then use point-slope formula:
y - y1 = m(x - x1)
y - 10 = -12(x - (-5))
y - 10 = -12(x + 5)
y - 10 = -12x - 60
y = -12x - 50
12x + y = -50
Reply:idk, calculator time
long stem roses
You know that when x=-5, y=10, so if you plug these into your y=mx+c formula:
10=-5m+c
You also know that when x=-4 y=-2, so if you plug these into your y=mx+c formula:
-2=-4m+c
You can now solve these as simultaneous equations:
Let equation 1 be 10=-5m+c
Let equation 2 be -2=-4m+c
Take equation 2 from equation 1:
12=-m
so m=-12
Plug this value into equation 1:
10=(-5*-12)+c
10=60+c
so c=-50
Therefore your y=mx+c equation is:
y=-12x-50
Rewriting for the form Ax+By=c:
12x+y=-50
Write the equatin of the line in standard form (Ax+By=C) that passes through points: (-5,10) and (-4,-2).?
first get the slope:
(-2 - 10) / (-4 - (-5) ) = -12/1 = -12
then use point-slope formula:
y - y1 = m(x - x1)
y - 10 = -12(x - (-5))
y - 10 = -12(x + 5)
y - 10 = -12x - 60
y = -12x - 50
12x + y = -50
Reply:idk, calculator time
long stem roses
What is y=3/4x + 3 in standard form [ax+by=C]?
i Just need the answer but it would be kind to explain how you got it..
=]
What is y=3/4x + 3 in standard form [ax+by=C]?
y = 3/2x + 3 (times both sides by 2)
2y = 3x + 6 (subtract both sides by 3x)
-3x + 2y = 6 and there you have it, it's in standard form!
Reply:Assume question is:-
y = (3/2) x + 3
2y = 3x + 6
3x - 2y = - 6
Reply:y= (3/2) x + 3
(Moving (3/2) x to the left side)
-(3/2) x + y = 3
(Comparing with ax + by = c)
Answer = a= -3/2; b= 1, c=3.
Simple.
Reply:All you need to do is move the x and y to the same side of the equation.
y = (3/2)x + 3
Subtract (3/2)x from both sides, because you have to do the same thing to both sides of the equation, and you get:
-(3/2)x + y = 3
A= -(3/2)
B= 1
C= 3
Reply:y = 3/4x + 3
4/3(3/4x - y) = 4/3(- 3)
x - 4/3y = - 4
Reply:y = 3/2x + 3
first clear the fraction by multiplying all three terms by the denominator 2
2y = 3x + 6
subtract 3x over to left side
-3x + 2y = 6
normally it is preferred to have the x term positive, so multiply through the equation by -1
3x - 2y = -6
=]
What is y=3/4x + 3 in standard form [ax+by=C]?
y = 3/2x + 3 (times both sides by 2)
2y = 3x + 6 (subtract both sides by 3x)
-3x + 2y = 6 and there you have it, it's in standard form!
Reply:Assume question is:-
y = (3/2) x + 3
2y = 3x + 6
3x - 2y = - 6
Reply:y= (3/2) x + 3
(Moving (3/2) x to the left side)
-(3/2) x + y = 3
(Comparing with ax + by = c)
Answer = a= -3/2; b= 1, c=3.
Simple.
Reply:All you need to do is move the x and y to the same side of the equation.
y = (3/2)x + 3
Subtract (3/2)x from both sides, because you have to do the same thing to both sides of the equation, and you get:
-(3/2)x + y = 3
A= -(3/2)
B= 1
C= 3
Reply:y = 3/4x + 3
4/3(3/4x - y) = 4/3(- 3)
x - 4/3y = - 4
Reply:y = 3/2x + 3
first clear the fraction by multiplying all three terms by the denominator 2
2y = 3x + 6
subtract 3x over to left side
-3x + 2y = 6
normally it is preferred to have the x term positive, so multiply through the equation by -1
3x - 2y = -6
How do you convert two points to standard form(ax+by=c)?
to be more specific, the points are A(6, -1) and B (-3, 7).
How do you convert two points to standard form(ax+by=c)?
1st: compute the slope(m) of the line passing through those points.
2nd: substitute the slope into the point-slope form of the equation of a line: (x-x1)=m(y-y1).
3rd: rearrange into the standard form
Reply:First get y on the LHS:
by = -ax + c
y(x) = (-a/b)x + c/b = mx + d
y(6) = m(6) + d = -1
y(-3) = m(-3) + d = 7
Subtract the second from the first:
9m = -8
m = -8/9 = -a/b by the eqn for y(x) above
(-8/9)(-3) + d = 7
8/3 + d = 7
d = 7 - 8/3 = 21/3 - 8/3 = 13/3 = c/b from above
a = 8, b = 9, c = 13/3 (3/3)b = 39/9 b, so c = 39
8x + 9y = 39 is the answer
Reply:y-(-1)/x-6 = 7-(-1)/-3-6
y+1/x-6 = 7+1/-9
-9(y+1) = 8(x-6)
-9y-9 = 8x-48
8x+9y = 48-9
8x+9y = 39
if u satisfied/want to know more pls contact me at sha_markf@yahoo.com
How do you convert two points to standard form(ax+by=c)?
1st: compute the slope(m) of the line passing through those points.
2nd: substitute the slope into the point-slope form of the equation of a line: (x-x1)=m(y-y1).
3rd: rearrange into the standard form
Reply:First get y on the LHS:
by = -ax + c
y(x) = (-a/b)x + c/b = mx + d
y(6) = m(6) + d = -1
y(-3) = m(-3) + d = 7
Subtract the second from the first:
9m = -8
m = -8/9 = -a/b by the eqn for y(x) above
(-8/9)(-3) + d = 7
8/3 + d = 7
d = 7 - 8/3 = 21/3 - 8/3 = 13/3 = c/b from above
a = 8, b = 9, c = 13/3 (3/3)b = 39/9 b, so c = 39
8x + 9y = 39 is the answer
Reply:y-(-1)/x-6 = 7-(-1)/-3-6
y+1/x-6 = 7+1/-9
-9(y+1) = 8(x-6)
-9y-9 = 8x-48
8x+9y = 48-9
8x+9y = 39
if u satisfied/want to know more pls contact me at sha_markf@yahoo.com
What's the standard functions for string process in C++?
I'm learning C++ programming. In my textbook, I only find some function for string processing such as "strcmp" or "strcat". But they are more widely used in old C. I want to know some newer function for string in C++, which process strings as "objects"?
If you know, tell me in detail (examples are best), Plz! Thanx.
What's the standard functions for string process in C++?
See: http://cplusplus.com/reference/string/st...
The page above describes what a string object is in C++ and gives details on its member functions and avaliable operations.
For example, assume:
std::string a = "Test"
std::string b = "Example"
Then, strcmp and strcat in C++ with string objects would be:
if ( a == b ) a+= b;
That is, if a is the same as B ( value wise ) then make a's value the sum of the value of a and b ("TestExample")
If you know, tell me in detail (examples are best), Plz! Thanx.
What's the standard functions for string process in C++?
See: http://cplusplus.com/reference/string/st...
The page above describes what a string object is in C++ and gives details on its member functions and avaliable operations.
For example, assume:
std::string a = "Test"
std::string b = "Example"
Then, strcmp and strcat in C++ with string objects would be:
if ( a == b ) a+= b;
That is, if a is the same as B ( value wise ) then make a's value the sum of the value of a and b ("TestExample")
Sunday, July 12, 2009
Write the equation in standard form Ax + By = C that passes through (4,6) and (0,0)?
First you find the slope of the line.
6-0/4-0 =3/2
Then you can find the equation using the point-slope formula.
y-y1= m(x-x1)
y-0=3/2(x-0)
y=3/2x
now to put it into standard form, you have to put the y and the x on both sides, so
-3/2x+y=0
BUT. the x must be positive soooo....
3/2x-y=0
Write the equation in standard form Ax + By = C that passes through (4,6) and (0,0)?
-3A + 2B = 0
-6A + 4B = 0
-12A+8B = 0
gifts
6-0/4-0 =3/2
Then you can find the equation using the point-slope formula.
y-y1= m(x-x1)
y-0=3/2(x-0)
y=3/2x
now to put it into standard form, you have to put the y and the x on both sides, so
-3/2x+y=0
BUT. the x must be positive soooo....
3/2x-y=0
Write the equation in standard form Ax + By = C that passes through (4,6) and (0,0)?
-3A + 2B = 0
-6A + 4B = 0
-12A+8B = 0
gifts
Putting Equations in standard form (Ax+By=C form)?
These two:
1. y - 1 = 1.5(x + 3)
2. y + 6 = -3.8(x - 2)
Please show work.
My daughter is doing it the x10 to get rid of decimal then divide by 10 at the end, but she's not sure what to do with the y when she does that???
Putting Equations in standard form (Ax+By=C form)?
y - 1 = 1.5(x + 3)
y - 1 = 1.5x + 4.5
-1.5x + y - 1 = 4.5
-1.5x + y = 5.5
------
y + 6 = -3.8(x - 2)
y + 6 = -3.8x + 7.6
3.8x + y + 6 = 7.6
3.8x + y = 1.6
Reply:to answer your question, i'd like to solve the first one
1. y - 1 = 1.5 (x+3)
now you're stating that she multiplies each side by 10 so...
10 * (y-1) = 10 * 1.5 * (x+3)
10 (y-1) = 15 * (x+3)
from here, she must distribute the 10 and the 15 on the left and right sides respectively
10 (y-1) = 15 * (x+3)
10*y- 10 * 1 = 15*x + 15 * 3
10y - 10 = 15x + 45
from what you've said, I think she's got it up to here
now she would need to get the variables, x and y, on one side of the equation, and the constants on the other
first, lets get the constants on one side of the equation
two ways to do it, both work:
a. add ten to both sides to cancel out the -10 on the left side of the equation
10y - 10 = 15x + 45
10y - 10 + 10 = 15x + 45 + 10
10y = 15x + 55
or
b. subtract 45 from each side to cancel out the 45 on the right hand side of the equation
10y - 10 = 15x + 45
10y - 10 - 45 = 15x + 45 - 45
10y - 55 = 15x
since all the constants are on one side in either case, now one must get all the variables to one side
**a. and b. are the last steps from previous a. and b.**
a. in this case, the constant, 55 is on the right. thus, the variables must be put on the left side of the equation. if you look on the right hand side, there is a 15x. to cancel this out, subtract 15x from both sides
10y = 15x + 55
10y - 15x = 15x - 15x + 55
10y - 15x = 55
***note: if i recall correctly, in standard form, there must be a positive constant before x. currently, it is -15. to make this positive, multiply both sides of the equation by -1
10y - 15x = 55
-1 * (10y - 15x) = -1 * 55
-10y + 15x = -55
15x -10y = -55
or
b. here, we have the opposite case of what was above. here the constant is on the left, so the variables must brought to the right hand side of the equation. to do this, subtract 10y from each side
10y - 55 = 15x
10y - 10y - 55 = 15x - 10y
-55 = 15x - 10y
***notice that both method a. and b. both are the same at this point. also notice that the constant before x, 15, is positive, and thus one does not need to multiply by the -1
from here the next step is to simplify as much as one can. some teachers may accept above equation as is for a time, but most want it simplified as much as possible
remember how in fractions, one looks for the greatest common factor and simplifies by it (ex. 12/3, the greatest common factor is 3, 12/3 = 4, 3/3 = 1, thus the fraction reduces to 4/1 or 4) the same principle is applied when solving equations
one must look at the equation and determine what the greatest common factor is to both sides of the equation
15x -10y = -55
looking at it, one might immediately tell that it is 5, if not, factor each constant, 15, 10, and -55
they factor into:
15: 3, 5
10: 2, 5
-55: -1, 5, 11
only one common to each is 5, thus 5 is the number you're looking for
divide each side by the greatest common factor, 5, to finally simplify the equation as much as is possible
15x - 10y = -55
(15x - 10y)/5 = -55/5
15x/5 - 10y/5 = -55/5
3x - 2y = -11
hope are able to tell what to do from that explanation, if not, feel free to message. I will help as much as I can.
1. y - 1 = 1.5(x + 3)
2. y + 6 = -3.8(x - 2)
Please show work.
My daughter is doing it the x10 to get rid of decimal then divide by 10 at the end, but she's not sure what to do with the y when she does that???
Putting Equations in standard form (Ax+By=C form)?
y - 1 = 1.5(x + 3)
y - 1 = 1.5x + 4.5
-1.5x + y - 1 = 4.5
-1.5x + y = 5.5
------
y + 6 = -3.8(x - 2)
y + 6 = -3.8x + 7.6
3.8x + y + 6 = 7.6
3.8x + y = 1.6
Reply:to answer your question, i'd like to solve the first one
1. y - 1 = 1.5 (x+3)
now you're stating that she multiplies each side by 10 so...
10 * (y-1) = 10 * 1.5 * (x+3)
10 (y-1) = 15 * (x+3)
from here, she must distribute the 10 and the 15 on the left and right sides respectively
10 (y-1) = 15 * (x+3)
10*y- 10 * 1 = 15*x + 15 * 3
10y - 10 = 15x + 45
from what you've said, I think she's got it up to here
now she would need to get the variables, x and y, on one side of the equation, and the constants on the other
first, lets get the constants on one side of the equation
two ways to do it, both work:
a. add ten to both sides to cancel out the -10 on the left side of the equation
10y - 10 = 15x + 45
10y - 10 + 10 = 15x + 45 + 10
10y = 15x + 55
or
b. subtract 45 from each side to cancel out the 45 on the right hand side of the equation
10y - 10 = 15x + 45
10y - 10 - 45 = 15x + 45 - 45
10y - 55 = 15x
since all the constants are on one side in either case, now one must get all the variables to one side
**a. and b. are the last steps from previous a. and b.**
a. in this case, the constant, 55 is on the right. thus, the variables must be put on the left side of the equation. if you look on the right hand side, there is a 15x. to cancel this out, subtract 15x from both sides
10y = 15x + 55
10y - 15x = 15x - 15x + 55
10y - 15x = 55
***note: if i recall correctly, in standard form, there must be a positive constant before x. currently, it is -15. to make this positive, multiply both sides of the equation by -1
10y - 15x = 55
-1 * (10y - 15x) = -1 * 55
-10y + 15x = -55
15x -10y = -55
or
b. here, we have the opposite case of what was above. here the constant is on the left, so the variables must brought to the right hand side of the equation. to do this, subtract 10y from each side
10y - 55 = 15x
10y - 10y - 55 = 15x - 10y
-55 = 15x - 10y
***notice that both method a. and b. both are the same at this point. also notice that the constant before x, 15, is positive, and thus one does not need to multiply by the -1
from here the next step is to simplify as much as one can. some teachers may accept above equation as is for a time, but most want it simplified as much as possible
remember how in fractions, one looks for the greatest common factor and simplifies by it (ex. 12/3, the greatest common factor is 3, 12/3 = 4, 3/3 = 1, thus the fraction reduces to 4/1 or 4) the same principle is applied when solving equations
one must look at the equation and determine what the greatest common factor is to both sides of the equation
15x -10y = -55
looking at it, one might immediately tell that it is 5, if not, factor each constant, 15, 10, and -55
they factor into:
15: 3, 5
10: 2, 5
-55: -1, 5, 11
only one common to each is 5, thus 5 is the number you're looking for
divide each side by the greatest common factor, 5, to finally simplify the equation as much as is possible
15x - 10y = -55
(15x - 10y)/5 = -55/5
15x/5 - 10y/5 = -55/5
3x - 2y = -11
hope are able to tell what to do from that explanation, if not, feel free to message. I will help as much as I can.
Dr. T K Duncan at Melrose Dental performed dental procedures that "doesn't meet the standard of care for the c
Dr. T K Duncan at Melrose Dental performed dental procedures that "doesn't meet the standard of care for the community" stated the California Dental Board. This contributed to bone and tooth loss.
Dr. T K Duncan at Melrose Dental performed dental procedures that "doesn't meet the standard of care for the c
I am at a loth of wordth.
Reply:ok....thanks
innia
Dr. T K Duncan at Melrose Dental performed dental procedures that "doesn't meet the standard of care for the c
I am at a loth of wordth.
Reply:ok....thanks
innia
How come the standard from Ax+By=C cannot be zero?
Can someone tell me why?
How come the standard from Ax+By=C cannot be zero?
The reason why A and B cannot both be zero is that if they are, the solution set is not a line. Rather, if A and B are both zero and C is also zero, the solution set is the entire plane, whereas if A and B are both zero and C is not zero, there are no solutions. Thus, to represent a line, it is necessary that at least one of A and B be nonzero.
Reply:Ummm, what cannot be 0? A,B, C, x, y,...?
The "standard form" is an equation. It doesn't make sense to say "an equation is zero." Only a number can be zero...
§
How come the standard from Ax+By=C cannot be zero?
The reason why A and B cannot both be zero is that if they are, the solution set is not a line. Rather, if A and B are both zero and C is also zero, the solution set is the entire plane, whereas if A and B are both zero and C is not zero, there are no solutions. Thus, to represent a line, it is necessary that at least one of A and B be nonzero.
Reply:Ummm, what cannot be 0? A,B, C, x, y,...?
The "standard form" is an equation. It doesn't make sense to say "an equation is zero." Only a number can be zero...
§
For standard form (Ax+by=c) If one is missing would it just be one?
like.. 4x=y
4x-y=1???
For standard form (Ax+by=c) If one is missing would it just be one?
Not sure exactly what you are asking but I will assume that it is what happens when one of the coefficients (a, b or c) is zero.
If a=0, you have by=c, or a horizontal line (parallel to the x-axis) at y=c/b.
If b=0, you haxe ax=c, or a vertical line (parallel to the y-axis) at x=c/a.
If c=0, you have ax + by=0, or a line with slope -a/b through the origin.
Reply:no
4x=y
4x-y=0
Reply:no
4x=y
=4x-y=0
4x-y=1???
For standard form (Ax+by=c) If one is missing would it just be one?
Not sure exactly what you are asking but I will assume that it is what happens when one of the coefficients (a, b or c) is zero.
If a=0, you have by=c, or a horizontal line (parallel to the x-axis) at y=c/b.
If b=0, you haxe ax=c, or a vertical line (parallel to the y-axis) at x=c/a.
If c=0, you have ax + by=0, or a line with slope -a/b through the origin.
Reply:no
4x=y
4x-y=0
Reply:no
4x=y
=4x-y=0
In standard form (Ax + By = C) can Ax be a negative?
Yes - depends on how the teacher wants the answer, though. You can always multiply both sides by -1 to make A a positive number if that looks better to you.
In standard form (Ax + By = C) can Ax be a negative?
yes why not the line has an other direction
Reply:Any of those variables can be negative including Ax.
Reply:Normally, the A constant should be positive. But if it comes out negative you can just factor out a -1 and make it positive. It doesn't change the meaning of the expression. Ask your teacher though, he/she may take it as a negative as well.
Reply:yes it can be Ax+By=C can be -Ax+By=c or Ax-By= c
Reply:yes it can. But for C to be positve, By must be greater than Ax
Reply:yes
In standard form (Ax + By = C) can Ax be a negative?
yes why not the line has an other direction
Reply:Any of those variables can be negative including Ax.
Reply:Normally, the A constant should be positive. But if it comes out negative you can just factor out a -1 and make it positive. It doesn't change the meaning of the expression. Ask your teacher though, he/she may take it as a negative as well.
Reply:yes it can be Ax+By=C can be -Ax+By=c or Ax-By= c
Reply:yes it can. But for C to be positve, By must be greater than Ax
Reply:yes
I received a certificate from F.C.I.C. Oxford WIS., for Soldering(MIL-Standard- 2000), in 1990, I need a copy.
I was an inmate at Oxford WIS., there I received a certificate for soldering, (MIL-Standard-2000). Somehow I've misplaced my certicate, and I need to know how to get intouch with the company (UNICOR), to try an obtain a copy of that certificate. UNICOR was a facility on the premises, that does contract for a variety of business. But this contract was for the Military, during the Gulf War, for which I obtain my skills in the field of Soldering.
I received a certificate from F.C.I.C. Oxford WIS., for Soldering(MIL-Standard- 2000), in 1990, I need a copy.
Contact the prison's work rehabilitation staff. They may have your certificate on file, or know how to get a copy.
gerbera
I received a certificate from F.C.I.C. Oxford WIS., for Soldering(MIL-Standard- 2000), in 1990, I need a copy.
Contact the prison's work rehabilitation staff. They may have your certificate on file, or know how to get a copy.
gerbera
Standard form Ax+By=C of y=1/2+7/2 , y=1/5x+2/5 , y=-3/7x+-5/7 , y= 4/3x+-3?
Dear Mr. xxxstarswirl...
For the linear equations in the standard form of Ax + By =C,
we have:
1). y = 1/2 + 7/2 = 8/2 = 4 the slope m = 0
and y=4
2). y = 1/5x + 2/5 the slope m = 1/5
y-intercept , b = 2/5
y-interception point is ( 0, 2/5)
[ multiplying by 5] 5y = x + 2
x - 5y + 2 = 0
3). y= -3/7x + -5/7 the slope m = -3/7
y-intercept, b = -5/7
y-interception point is ( 0, -5/7)
[multiplying by 7] 7y = -3x - 5
3x + 7y + 5 = 0
4). y = 4/3x + -3 the slope m = 4/3
y-intercept, b = -3
y-interception point is ( 0, -3)
[multiplying by 3] 3y = 4x - 9
4x - 3y - 9=0
Thank you for your problem, and thank you for the opportunity of sharing in its computations.
Sincerely,
willard_thomas_jr@yahoo.com
(a.k.a. calvaliear)
For the linear equations in the standard form of Ax + By =C,
we have:
1). y = 1/2 + 7/2 = 8/2 = 4 the slope m = 0
and y=4
2). y = 1/5x + 2/5 the slope m = 1/5
y-intercept , b = 2/5
y-interception point is ( 0, 2/5)
[ multiplying by 5] 5y = x + 2
x - 5y + 2 = 0
3). y= -3/7x + -5/7 the slope m = -3/7
y-intercept, b = -5/7
y-interception point is ( 0, -5/7)
[multiplying by 7] 7y = -3x - 5
3x + 7y + 5 = 0
4). y = 4/3x + -3 the slope m = 4/3
y-intercept, b = -3
y-interception point is ( 0, -3)
[multiplying by 3] 3y = 4x - 9
4x - 3y - 9=0
Thank you for your problem, and thank you for the opportunity of sharing in its computations.
Sincerely,
willard_thomas_jr@yahoo.com
(a.k.a. calvaliear)
What would C#, F, G, A# Be in Standard Chord Symbol Notation?
So I was writing down chords to a jazz song I've been writing and stumbled upon this Chord which I can't figure out what the name of it is. I'm writing the song out like a FakeBook style, so I didn't how to put in Chord Symbol, or just the plain name of it. I've a asked a few friends of mine, and two said it would be a C# Fully Diminished. But I want to be sure. If you could please leave the full name of the chord, and the chord symbol. Thanks a lot. Again the notes from low to high are C#, F, G, A#. The song is for Piano.
What would C#, F, G, A# Be in Standard Chord Symbol Notation?
I think it is actually a G half diminished just spelled enharmonically. G A#/Bb C#/Db F. You just have it in 3rd inversion so it would be G(half dim symbol)7/Db
If you are going with the Bbmin6, you just write it as Bbmin/Db
Reply:It's not diminished. I'd write it as: C#(b5/b7)
What would C#, F, G, A# Be in Standard Chord Symbol Notation?
I think it is actually a G half diminished just spelled enharmonically. G A#/Bb C#/Db F. You just have it in 3rd inversion so it would be G(half dim symbol)7/Db
If you are going with the Bbmin6, you just write it as Bbmin/Db
Reply:It's not diminished. I'd write it as: C#(b5/b7)
C++ Program to calculate mean variance & standard deviation?formula is given as:?
variance=
N ―
1/N ∑ (x ı – x)²
i=1
standard deviation= √(variance)
− N
where x =1/N ∑ Xı
i=1
C++ Program to calculate mean variance %26amp; standard deviation?formula is given as:?
When you see ∑, you need a loop that adds up your Xi's or whatever is input to the ∑, which should be in an array. The rest of it is just math.
N ―
1/N ∑ (x ı – x)²
i=1
standard deviation= √(variance)
− N
where x =1/N ∑ Xı
i=1
C++ Program to calculate mean variance %26amp; standard deviation?formula is given as:?
When you see ∑, you need a loop that adds up your Xi's or whatever is input to the ∑, which should be in an array. The rest of it is just math.
Which substance will have the highest standard molar entropy at 25°C?
A. C(graphite)
B. C2H4(g)
C. CH3OH(l)
D. MgCO3(s)
E. Cannot be determined!
Which substance will have the highest standard molar entropy at 25°C?
B. C2H4(g)
rosemary
B. C2H4(g)
C. CH3OH(l)
D. MgCO3(s)
E. Cannot be determined!
Which substance will have the highest standard molar entropy at 25°C?
B. C2H4(g)
rosemary
C++ Function to compute average and standard deviation?
The books asks me to the following: Write a function that computes the average and standard deviation of four scores. The standard deviation is defined to be the square root of the average of the four values: (si - a)2 where a is the average of the four scores s1, s2, s3, and s4. The function will have six parameters and will call two other functions. Embed the function in a driver program that allows you to test the function again and again until you tell the program you are finished.
I am given a program:
http://www.forex1000.com/codegiven.txt
But my professor said:
http://www.forex1000.com/codeasked.txt
I am unsure of where to make the corrections for half of the parameters are gone... Any help or any hint toward what to do would be greatly appreciated.
Thanks
C++ Function to compute average and standard deviation?
Actually, you've got everything you need - all you need to do is write a driver that inputs the numbers (say, n1, n2, n3, n4), and then you can call the following:
double avg = myMean(n1,n2,n3,n4);
double stdev = myStdev(n1,n2,n3,n4);
displayStats(n1,n2,n3,n4);
There is some redundancy here though. Typically, all you'd really have to do is call the displayStats function and that would call the others:
double myStdev(double n1, double n2, double n3, double n4)
{
double avg = myMean(n1, n2, n3, n4);
// Calculate stdev below using four numbers and average
double stdev;
...
return stdev;
}
void displayStats(double n1, double n2, double n3, double n4)
{
double avg = myMean(n1, n2, n3, n4);
double stdev = myStdev(n1, n2, n3, n4);
cout %26gt;%26gt; "\nAverage = " %26gt;%26gt; avg %26gt;%26gt; "." %26gt;%26gt; endl;
cout %26gt;%26gt; "\nStandard Deviation = " %26gt;%26gt; stdev %26gt;%26gt; "." %26gt;%26gt; endl;
}
I am given a program:
http://www.forex1000.com/codegiven.txt
But my professor said:
http://www.forex1000.com/codeasked.txt
I am unsure of where to make the corrections for half of the parameters are gone... Any help or any hint toward what to do would be greatly appreciated.
Thanks
C++ Function to compute average and standard deviation?
Actually, you've got everything you need - all you need to do is write a driver that inputs the numbers (say, n1, n2, n3, n4), and then you can call the following:
double avg = myMean(n1,n2,n3,n4);
double stdev = myStdev(n1,n2,n3,n4);
displayStats(n1,n2,n3,n4);
There is some redundancy here though. Typically, all you'd really have to do is call the displayStats function and that would call the others:
double myStdev(double n1, double n2, double n3, double n4)
{
double avg = myMean(n1, n2, n3, n4);
// Calculate stdev below using four numbers and average
double stdev;
...
return stdev;
}
void displayStats(double n1, double n2, double n3, double n4)
{
double avg = myMean(n1, n2, n3, n4);
double stdev = myStdev(n1, n2, n3, n4);
cout %26gt;%26gt; "\nAverage = " %26gt;%26gt; avg %26gt;%26gt; "." %26gt;%26gt; endl;
cout %26gt;%26gt; "\nStandard Deviation = " %26gt;%26gt; stdev %26gt;%26gt; "." %26gt;%26gt; endl;
}
How do u write the line that passes thporugh (4,-2) and (2,-4) in standard ax+by=c form without switching vari
ables during ur work
How do u write the line that passes thporugh (4,-2) and (2,-4) in standard ax+by=c form without switching vari
First, you need to calculate the slope:
change in y = -4 - -2 = -2
change in x = 2 - 4 = -2
Thus the slope = -2 / -2 = 1
Using the point slope equation of a line (and either point, I'll use the first point), the equation of the line is:
y - -2 = 1 (x - 4), so
y+2 = x-4, and collecting terms
x - y = 6
Now we check the two points are on this line:
4 - -2 = 6 yes!
2 - -4 = 6 yes!
Reply:y = (ax + c)/b where your slope = a/b and your y-int = c/b
slope = rise/run = -2/-2; therefore a = -2 = b
pick a point, say (4, -2) and plug in for x and y, and solve for c, the only variable you have left to solve for yielding
x - y- 6 =0
Reply:slope,m=2/2=1
EQ is
y+2=1(x-4).
x-y-6=0
Reply:First in order to write the line that passes through the points given you have to find the slope. You can find slope by the formula y2-y1/x2-x1 which = 1
x-y=6
check 4--2=6
check 2--4=6
They both check out
Best of luck
How do u write the line that passes thporugh (4,-2) and (2,-4) in standard ax+by=c form without switching vari
First, you need to calculate the slope:
change in y = -4 - -2 = -2
change in x = 2 - 4 = -2
Thus the slope = -2 / -2 = 1
Using the point slope equation of a line (and either point, I'll use the first point), the equation of the line is:
y - -2 = 1 (x - 4), so
y+2 = x-4, and collecting terms
x - y = 6
Now we check the two points are on this line:
4 - -2 = 6 yes!
2 - -4 = 6 yes!
Reply:y = (ax + c)/b where your slope = a/b and your y-int = c/b
slope = rise/run = -2/-2; therefore a = -2 = b
pick a point, say (4, -2) and plug in for x and y, and solve for c, the only variable you have left to solve for yielding
x - y- 6 =0
Reply:slope,m=2/2=1
EQ is
y+2=1(x-4).
x-y-6=0
Reply:First in order to write the line that passes through the points given you have to find the slope. You can find slope by the formula y2-y1/x2-x1 which = 1
x-y=6
check 4--2=6
check 2--4=6
They both check out
Best of luck
If u c a black wiry standard schnauzer in carolina?
could u plz answer tht u hv?????? i love him very very very very very very very very much he comes to miles and has a shock collar on!
If u c a black wiry standard schnauzer in carolina?
try posting an add in your local paper, also if you have a picture of him you can make copies and put up lost signs, most conviencence stores will let you post them, also call the local rescue groups, animal shelters, and dog pounds in your area someone may have picked him up already, also make sure you alert your friends and neighbors so they can keep an eye out too, i really hope you find him i know how hard it is to lose a pet, when you get him back i would recommend getting him microchipped, a lot of animal shelters have scanners nowadays, and if found will contact you, the success rate of finding a lost pet is much higher when they are microchipped hope this helps good luck
Reply:i dont get your question
Reply:hope you find him--my white shih-tzu went missing in Fl back in April-i miss her terribbly
If u c a black wiry standard schnauzer in carolina?
try posting an add in your local paper, also if you have a picture of him you can make copies and put up lost signs, most conviencence stores will let you post them, also call the local rescue groups, animal shelters, and dog pounds in your area someone may have picked him up already, also make sure you alert your friends and neighbors so they can keep an eye out too, i really hope you find him i know how hard it is to lose a pet, when you get him back i would recommend getting him microchipped, a lot of animal shelters have scanners nowadays, and if found will contact you, the success rate of finding a lost pet is much higher when they are microchipped hope this helps good luck
Reply:i dont get your question
Reply:hope you find him--my white shih-tzu went missing in Fl back in April-i miss her terribbly
How do you tune to c i can tune standard and drop D but not drop C i dont understand what c is? please help?
I assume you're trying to tune a guitar to drop-C? It's the same principle as drop-D, except down one step further. Simply stated (from low to high):
Standard: E-A-D-G-B-E
Drop-D: D-A-D-G-B-E
D (everything down one full step): D-G-C-F-A-D
Drop-C: C-G-C-F-A-D
You'll hear drop-C on (amongst many others) Metallica's "St. Anger" and just about everything by System Of A Down *prior to* "Mezmerize/Hypnotize" (which was drop-D, down half a step: Db-Ab-Db-Gb-Bb-Eb).
It can be quite a pain to tune a guitar to these tunings without the use of a chromatic tuner, so I'd definitely recommend you get one if you don't have one already. If you don't and you're planning to get one, make sure it'll allow you to tune to any note (A-B-C-D-E-F-G) and that it has a half-step (# or b) indicator for those half-step notes.
How do you tune to c i can tune standard and drop D but not drop C i dont understand what c is? please help?
heres a cool link
Reply:what instrument are you trying to tune?
and do you want to know how to tune to standard or drop c?
Reply:what!!
Reply:c is nirvana
wallflower
Standard: E-A-D-G-B-E
Drop-D: D-A-D-G-B-E
D (everything down one full step): D-G-C-F-A-D
Drop-C: C-G-C-F-A-D
You'll hear drop-C on (amongst many others) Metallica's "St. Anger" and just about everything by System Of A Down *prior to* "Mezmerize/Hypnotize" (which was drop-D, down half a step: Db-Ab-Db-Gb-Bb-Eb).
It can be quite a pain to tune a guitar to these tunings without the use of a chromatic tuner, so I'd definitely recommend you get one if you don't have one already. If you don't and you're planning to get one, make sure it'll allow you to tune to any note (A-B-C-D-E-F-G) and that it has a half-step (# or b) indicator for those half-step notes.
How do you tune to c i can tune standard and drop D but not drop C i dont understand what c is? please help?
heres a cool link
Reply:what instrument are you trying to tune?
and do you want to know how to tune to standard or drop c?
Reply:what!!
Reply:c is nirvana
wallflower
Is c++ tr1 an aproved standard?
Is there one complete implementation?
Is c++ tr1 an aproved standard?
This is a Computers and Internet question, not a mathematics question. I suggest you post it to the appropriate forum
Is c++ tr1 an aproved standard?
This is a Computers and Internet question, not a mathematics question. I suggest you post it to the appropriate forum
What do the a, b, and c stand for in the standard form equation?
Ax +By = C
what do they stand for??????????
What do the a, b, and c stand for in the standard form equation?
Unknown coefficients. A,B, and C could be whatever you specify. In other words, the equation above is a generalized form.
Reply:the missing number you have to fine out to solve the problem
Reply:A is the coefficient of x and B is the coefficient of y. C is a constant as are A and B.
If you put this equation in slope intercept form you get
y = -Ax/B + C/B
So - A/B is the slope and C/b is the y- intercept.
Reply:Numerical constants.
what do they stand for??????????
What do the a, b, and c stand for in the standard form equation?
Unknown coefficients. A,B, and C could be whatever you specify. In other words, the equation above is a generalized form.
Reply:the missing number you have to fine out to solve the problem
Reply:A is the coefficient of x and B is the coefficient of y. C is a constant as are A and B.
If you put this equation in slope intercept form you get
y = -Ax/B + C/B
So - A/B is the slope and C/b is the y- intercept.
Reply:Numerical constants.
ISO/ANSI C++ Standards and Compiles?
Hi,
What is the latest ISO/ANSI C++ standard? Which company has the compiles that provide the most compliance to that standard?
Is there a new ISO/ANSI standard underway?
ISO/ANSI C++ Standards and Compiles?
September 28, 1998 -- International Standard 14882:1998 - Programming Language C++ has been approved as an American National Standard.
The National Committee for Information Technology Standards has requested its Secretariat to promote the use of standards developed by NCITS and JTC 1 by distributing standards electronically through a Web Storefront at heavily discounted prices, as a service to the standards community as well as providing affordable standards to totally new customers. ANSI has also agreed to participate in this C++ experiment.
We are offering C++ for sale in soft copy only for $18 through our office at 202-626-5740. Other standards, such as NCITS 319:1998, Programming Language Smalltalk, will be included in this experiment as they become available.
IS 14882 is available in hard copy from ANSI (212-642-4900) for $175.
For further information about C++ or NCITS J16, the C++ development committee, please contact Deborah Donovan at ddonovan@itic.org.
What is the latest ISO/ANSI C++ standard? Which company has the compiles that provide the most compliance to that standard?
Is there a new ISO/ANSI standard underway?
ISO/ANSI C++ Standards and Compiles?
September 28, 1998 -- International Standard 14882:1998 - Programming Language C++ has been approved as an American National Standard.
The National Committee for Information Technology Standards has requested its Secretariat to promote the use of standards developed by NCITS and JTC 1 by distributing standards electronically through a Web Storefront at heavily discounted prices, as a service to the standards community as well as providing affordable standards to totally new customers. ANSI has also agreed to participate in this C++ experiment.
We are offering C++ for sale in soft copy only for $18 through our office at 202-626-5740. Other standards, such as NCITS 319:1998, Programming Language Smalltalk, will be included in this experiment as they become available.
IS 14882 is available in hard copy from ANSI (212-642-4900) for $175.
For further information about C++ or NCITS J16, the C++ development committee, please contact Deborah Donovan at ddonovan@itic.org.
How much marks need to pass in 9th standard for i.c.s.e?
you need 33 marks in each subject
How much marks need to pass in 9th standard for i.c.s.e?
u need 2 score max 40% in each subject.
Reply:Actually the passing standard can vary from school to school in case of std-IX as the ICSE board does not directly conduct the exams in IX. Std-IX has 4 compulsory subjects: Eng, 2nd Lang, Social Studies and Env. Edn. In these subjects the minimum pass mark is 35 and the average pass mark is 40 and you should not fail in more than one optional subjects.
Reply:98.9 %
Reply:I.C.S.E. and I.S.C. Examinations of the Council for the Indian School Certificate Examination, New Delhi.
For Class IX
Compulsory pass in English, Second Language, SUPW, History, Civics and Geography and any two other subjects. The pass mark for each subject is 40%.
hollyhock
How much marks need to pass in 9th standard for i.c.s.e?
u need 2 score max 40% in each subject.
Reply:Actually the passing standard can vary from school to school in case of std-IX as the ICSE board does not directly conduct the exams in IX. Std-IX has 4 compulsory subjects: Eng, 2nd Lang, Social Studies and Env. Edn. In these subjects the minimum pass mark is 35 and the average pass mark is 40 and you should not fail in more than one optional subjects.
Reply:98.9 %
Reply:I.C.S.E. and I.S.C. Examinations of the Council for the Indian School Certificate Examination, New Delhi.
For Class IX
Compulsory pass in English, Second Language, SUPW, History, Civics and Geography and any two other subjects. The pass mark for each subject is 40%.
hollyhock
How do i tune a guitar from standard to drop C?
guitar tunings
How do i tune a guitar from standard to drop C?
Your tuning to CGCFAD
So...
Play the 3rd fret Low E string and the A string open. Retune the A string to match the 3rd fret Low E string.
Play the 5th fret A string and the D string open. Retune the D string to match the 5th fret A string.
Play the 5th fret D string and the G string open. Retune the G string to match the 5th fret D string.
Play the 4th fret G string and the B string open. Retune the B string to match the 4th fret G string.
Play the 5th fret B string and the High E string open. Retune the High E string to match the 5th fret B string.
Play the 12th fret Low E string and the D string open. Retune the 12th fret Low E to match the D string open.
Reply:tune everything down one step, and your low string an extra step
email me and I'll help you with any technical, or "getting started" questions
*FOR EXAMPLE: in getting started, to do dropped D, you tune down until your low string's 7th fret matches the A string's pitch above it, instead of using the 5th fret...but for dropped C, you use the 9th fret. Thus tune it DOWN until the 7th fret matches the C
for the "A string" again, just tune down, til the 7th fret matches the D string above it
the only "trick" is remembering that the "switchup" is using the 6th fret instead of the 4th, when it comes to tuning the "G string" to the "B pitched string"
the real benefit of "dropped tuning" is to play low power chords with one, or even no (for the C chord in this case), fingers
Reply:buy a guitar tuner at guitar center for like $20.
plug your guitar into the tuner and strum and adjust the keys untill it is at drop C.
Reply:tune down the strings to these keys
1.D
2.A
3.F
4.C
5.G
6.C
How do i tune a guitar from standard to drop C?
Your tuning to CGCFAD
So...
Play the 3rd fret Low E string and the A string open. Retune the A string to match the 3rd fret Low E string.
Play the 5th fret A string and the D string open. Retune the D string to match the 5th fret A string.
Play the 5th fret D string and the G string open. Retune the G string to match the 5th fret D string.
Play the 4th fret G string and the B string open. Retune the B string to match the 4th fret G string.
Play the 5th fret B string and the High E string open. Retune the High E string to match the 5th fret B string.
Play the 12th fret Low E string and the D string open. Retune the 12th fret Low E to match the D string open.
Reply:tune everything down one step, and your low string an extra step
email me and I'll help you with any technical, or "getting started" questions
*FOR EXAMPLE: in getting started, to do dropped D, you tune down until your low string's 7th fret matches the A string's pitch above it, instead of using the 5th fret...but for dropped C, you use the 9th fret. Thus tune it DOWN until the 7th fret matches the C
for the "A string" again, just tune down, til the 7th fret matches the D string above it
the only "trick" is remembering that the "switchup" is using the 6th fret instead of the 4th, when it comes to tuning the "G string" to the "B pitched string"
the real benefit of "dropped tuning" is to play low power chords with one, or even no (for the C chord in this case), fingers
Reply:buy a guitar tuner at guitar center for like $20.
plug your guitar into the tuner and strum and adjust the keys untill it is at drop C.
Reply:tune down the strings to these keys
1.D
2.A
3.F
4.C
5.G
6.C
How can i usee " itoa " function of standard library in C++ ????
i dont know how to use it n wats the syntex .............
if Y is some integer and i want to put its value in char Z ....by using itoa function ....how will i do it and also what is that 3rd argument (ie an int) in that function plzzzzzzzzzzzzz help mee
How can i usee " itoa " function of standard library in C++ ????
It Converts an integer into a string. This is not ANSI C.
It defined in stdlib.h
syntax id : char *itoa( int value, char *string, int radix );
itoa converts the integer val into a string using radix as the base.
value
Is the integer to be converted to string representation.
string
Points to the buffer that is to hold resulting string. The resulting string may be as long as seventeen bytes.
radix
Is the base of the number; must be in the range 2 - 36.
itoa() is not in the standard C library.
it acts like strtol() with base 10.But, if the value of the
integer is outside the range of an int the behaviour is undefined.
strtol() and strtoul() are recommended instead of atoi(). You can also choose a base from 0 to 36. Open your C-book for detail.
If you want to convert integer Y to a char Z then try
char *z = itoa( y, char *str, 10);
I assumed here you are converting a number of base10.
this function returns the string str.. and that we are storing in z.
Hope you understood.
Reply:The first parameter is the integer. The second is the char*. The third parameter is the maximum length of the char string. E.g.
itoa(nInt, szBuf, sizeof(szBuf));
if Y is some integer and i want to put its value in char Z ....by using itoa function ....how will i do it and also what is that 3rd argument (ie an int) in that function plzzzzzzzzzzzzz help mee
How can i usee " itoa " function of standard library in C++ ????
It Converts an integer into a string. This is not ANSI C.
It defined in stdlib.h
syntax id : char *itoa( int value, char *string, int radix );
itoa converts the integer val into a string using radix as the base.
value
Is the integer to be converted to string representation.
string
Points to the buffer that is to hold resulting string. The resulting string may be as long as seventeen bytes.
radix
Is the base of the number; must be in the range 2 - 36.
itoa() is not in the standard C library.
it acts like strtol() with base 10.But, if the value of the
integer is outside the range of an int the behaviour is undefined.
strtol() and strtoul() are recommended instead of atoi(). You can also choose a base from 0 to 36. Open your C-book for detail.
If you want to convert integer Y to a char Z then try
char *z = itoa( y, char *str, 10);
I assumed here you are converting a number of base10.
this function returns the string str.. and that we are storing in z.
Hope you understood.
Reply:The first parameter is the integer. The second is the char*. The third parameter is the maximum length of the char string. E.g.
itoa(nInt, szBuf, sizeof(szBuf));
Yo!I have a normal bog-standard Dell p.c from 2003. Can I watch tv on it? What hard/software do i need? Peace.
you will need a tv tuner. i have seen them on ebay for about £30 USB ones.
you will get all the software with it.
Yo!I have a normal bog-standard Dell p.c from 2003. Can I watch tv on it? What hard/software do i need? Peace.
Happauge Nova-TD is a USB dual freeview tuner. Software wise it comes with some but think of it getting started software as you can get better software codec wise purevideo (nvidia) is one of the better quality codec. for MCE functions you've got the likes of media portal or GB-PVR. Which gives you alot of functions for TV, DVD videos etc etc.
If you can fit a full size PCI card then the nova-t 500 be better but otherwise the top one will do everything that 500 does.
you will get all the software with it.
Yo!I have a normal bog-standard Dell p.c from 2003. Can I watch tv on it? What hard/software do i need? Peace.
Happauge Nova-TD is a USB dual freeview tuner. Software wise it comes with some but think of it getting started software as you can get better software codec wise purevideo (nvidia) is one of the better quality codec. for MCE functions you've got the likes of media portal or GB-PVR. Which gives you alot of functions for TV, DVD videos etc etc.
If you can fit a full size PCI card then the nova-t 500 be better but otherwise the top one will do everything that 500 does.
How do i do this algebra problem in standard form(Ax + By = C)?
how do i do this algebra problem in standard form?
y= 9x + 1
How do i do this algebra problem in standard form(Ax + By = C)?
y-9x=1
-9x+y=1
Reply:You have to get the X and the y on the same side, so, subtract 9x
from each side:
y= 9x + 1
So now you have: -9x +y =1
Its in standard from now.
.
Reply:Just move stuff around by doing the same thing to both sides of the equation:
First, subtract one y from each side:
0 = 9x - y + 1
Then subtract 1 from each side:
-1 = 9x - y
Then you can flip it if you want:
9x - y = -1
And:
A = 9
B = -1
C = -1
Reply:y=9x+1
y-9x=9x-9x+1
-9x+y=1
9x-y=-1, in which a=9, b=-1, and c=-1
Reply:In standard form "A" cannot be negative, so y=9x+1 becomes:
9x -y = -1
that's it! ;)
Reply::] ok
first you subsitute y= 9x+1 into Ax+By= C
you get Ax+B(9x+1)=C
distribute Ax+9B+B=C
put in standard form x(A+9B)+B=C
simplify x= C-B/ A+9B
cabbage
y= 9x + 1
How do i do this algebra problem in standard form(Ax + By = C)?
y-9x=1
-9x+y=1
Reply:You have to get the X and the y on the same side, so, subtract 9x
from each side:
y= 9x + 1
So now you have: -9x +y =1
Its in standard from now.
.
Reply:Just move stuff around by doing the same thing to both sides of the equation:
First, subtract one y from each side:
0 = 9x - y + 1
Then subtract 1 from each side:
-1 = 9x - y
Then you can flip it if you want:
9x - y = -1
And:
A = 9
B = -1
C = -1
Reply:y=9x+1
y-9x=9x-9x+1
-9x+y=1
9x-y=-1, in which a=9, b=-1, and c=-1
Reply:In standard form "A" cannot be negative, so y=9x+1 becomes:
9x -y = -1
that's it! ;)
Reply::] ok
first you subsitute y= 9x+1 into Ax+By= C
you get Ax+B(9x+1)=C
distribute Ax+9B+B=C
put in standard form x(A+9B)+B=C
simplify x= C-B/ A+9B
cabbage
The reaction is at standard 25 degrees C. Determine E (the measured voltage)?
Cd (s) + Pb^2+ (aq, 0.150 M) %26lt;-%26gt; Pb(s) + Cd^2+ (aq, 0.0250 M) calculate the Kc, the equilibrium constant, for the cell reaction.
E= ___________
Kc= ___________
The reaction is at standard 25 degrees C. Determine E (the measured voltage)?
Find E0 from standard potentials.
Use DeltaG0 = -nFE0 (energy = voltage x charge) to find standard free energy from E0
As usual, use DeltaG0 =-RT ln K
To find actual cell potential, apply Nernst equation separately to each electrode.
Good luck.
E= ___________
Kc= ___________
The reaction is at standard 25 degrees C. Determine E (the measured voltage)?
Find E0 from standard potentials.
Use DeltaG0 = -nFE0 (energy = voltage x charge) to find standard free energy from E0
As usual, use DeltaG0 =-RT ln K
To find actual cell potential, apply Nernst equation separately to each electrode.
Good luck.
Which is the best standard book for c++,.net please tell?
books prefered
Which is the best standard book for c++,.net please tell?
For the c++ the best book is by Robert Laffore.
It is of Galgotia Publication and book name is Object Oriented Programming in Turbo C++ Balagurusami is also good book but for using that book you should have a good knowledge of C++.
Robert Laffore is best for beginners as well as experts
Reply:i think BALAGURUSWAMY is the best 4 c++
Reply:Bruce Eckel's MindView, Inc: Thinking in C++ 2nd Edition by Bruce Eckel
This two volume book, which covers Standard C++, is available free on-line. ... you for your book 'Thinking in C++' which is, with no doubt, the best book I ...
http://www.mindview.net/Books/TICPP/Thin...
Reply:T Ramachandran is the best books for C++.
Download some books which mey be useful to u from here
http://www.download-googlesearch.blogspo...
Reply:Balaguru swami is for kid. beat book on c++ Author "kanitkar"
Reply:Collection of Free-e-Books on C++ Programming Language
1. C++ GUI Programming with Qt 3 ( Author:Jasmin Blanchette, Mark Summerfield ISBN:0131240722 Pages:464 Publication Date:January 15, 2004 Publisher:Prentice Hall PTR )
2. Visual C++ 6 Unleashed ( First Printing:July, 2000)
3. An Introduction to C++ Programming( Author:Björn Fahller)
4. An Overview Of The C++ Programming Langauge( Author:Bjarne Stroustrup)
5. How To Think Like A Computer Scientist With C++( Author:Allen B. Downey)
6. Introduction to OOP Using C++( Author:Peter Müller)
7. A Beginner's C++( Author:Neil Gray)
8. Programming in C++ - Rules and Recommendations( Author:FN/Mats Henricson and Erik Nyquist)
9. Thinking in C++ Volume 1 - Introduction to Standard C++( Author:Bruce Eckel)
10. Thinking in C++ Volume 2 - Practical Programming( Author:Bruce Eckel, Chuck Allison)
11. C++ In Action - Industrial Strength Programming Techniques( Author:Bartosz Milewski)
Which is the best standard book for c++,.net please tell?
For the c++ the best book is by Robert Laffore.
It is of Galgotia Publication and book name is Object Oriented Programming in Turbo C++ Balagurusami is also good book but for using that book you should have a good knowledge of C++.
Robert Laffore is best for beginners as well as experts
Reply:i think BALAGURUSWAMY is the best 4 c++
Reply:Bruce Eckel's MindView, Inc: Thinking in C++ 2nd Edition by Bruce Eckel
This two volume book, which covers Standard C++, is available free on-line. ... you for your book 'Thinking in C++' which is, with no doubt, the best book I ...
http://www.mindview.net/Books/TICPP/Thin...
Reply:T Ramachandran is the best books for C++.
Download some books which mey be useful to u from here
http://www.download-googlesearch.blogspo...
Reply:Balaguru swami is for kid. beat book on c++ Author "kanitkar"
Reply:Collection of Free-e-Books on C++ Programming Language
1. C++ GUI Programming with Qt 3 ( Author:Jasmin Blanchette, Mark Summerfield ISBN:0131240722 Pages:464 Publication Date:January 15, 2004 Publisher:Prentice Hall PTR )
2. Visual C++ 6 Unleashed ( First Printing:July, 2000)
3. An Introduction to C++ Programming( Author:Björn Fahller)
4. An Overview Of The C++ Programming Langauge( Author:Bjarne Stroustrup)
5. How To Think Like A Computer Scientist With C++( Author:Allen B. Downey)
6. Introduction to OOP Using C++( Author:Peter Müller)
7. A Beginner's C++( Author:Neil Gray)
8. Programming in C++ - Rules and Recommendations( Author:FN/Mats Henricson and Erik Nyquist)
9. Thinking in C++ Volume 1 - Introduction to Standard C++( Author:Bruce Eckel)
10. Thinking in C++ Volume 2 - Practical Programming( Author:Bruce Eckel, Chuck Allison)
11. C++ In Action - Industrial Strength Programming Techniques( Author:Bartosz Milewski)
How do you write this is standard form? (Ax + By =c?
(Ax + By =C)
Point is (2,1)
Slope is 4
How do you write this is standard form? (Ax + By =c?
-4x+y=-7
OR
4x-y=7
Point is (2,1)
Slope is 4
How do you write this is standard form? (Ax + By =c?
-4x+y=-7
OR
4x-y=7
In which ASTM standard is Reference Fuel C defined?
Reference Fuel C is required in many tests of rubber and polymer chemical resistance, but where is it defined?
In which ASTM standard is Reference Fuel C defined?
I believe ASTM D471 is your best bet. My recollection is that Reference Fuel C is composed of 50% isooctane and 50% toluene. Hope this helps.
phlox
In which ASTM standard is Reference Fuel C defined?
I believe ASTM D471 is your best bet. My recollection is that Reference Fuel C is composed of 50% isooctane and 50% toluene. Hope this helps.
phlox
What is the standard format for beginning C++ code (pre-code text)?
I've found multiple suggestions, and am curious about the "best" or most widely used. I'm a novice C++ programmer, and am wondering what the most common basic beginning of a C++ source is.
What is the standard format for beginning C++ code (pre-code text)?
For most of the applications that you will be writing in an introduction course, your source will be laid out as follows:
// helloworld.cpp
// 27 June 2007
// Print "Hello World!" to the console.
// Include necessary headers
#include %26lt;iostream%26gt;
// Use the standard name space
using namespace std;
// Main entry point
int main() {
cout %26lt;%26lt; "Hello World!\n";
return 0;
}
Reply:/*The following is pretty standard: Dont forget to comment */
# include %26lt;time.h%26gt; //Header files
main ()
{
application code goes here
}
Reply:#include %26lt;headerfile(s)%26gt;
#define %26lt;global constant(s)%26gt;
%26lt;global function(s)%26gt;
int main()
{
%26lt;main program%26gt;
}
Reply:You need to clarify what you mean. Are you referring to the comments often seen at the beginning of a source file? Or do you mean actual code? Sorry, but I can't do mind reading, so you will have to add in additional details or repost your question, spelling out exactly what you mean.
I suggest you take a look at popular C and C++ libraries. SGI's STLPort, some of the more well-known libraries on Sourceforge, and so on, are good starting points. Exploring the Linux kernel code will allow you to see how they structure their source files as well.
And for the record, there is no standard format.
What is the standard format for beginning C++ code (pre-code text)?
For most of the applications that you will be writing in an introduction course, your source will be laid out as follows:
// helloworld.cpp
// 27 June 2007
// Print "Hello World!" to the console.
// Include necessary headers
#include %26lt;iostream%26gt;
// Use the standard name space
using namespace std;
// Main entry point
int main() {
cout %26lt;%26lt; "Hello World!\n";
return 0;
}
Reply:/*The following is pretty standard: Dont forget to comment */
# include %26lt;time.h%26gt; //Header files
main ()
{
application code goes here
}
Reply:#include %26lt;headerfile(s)%26gt;
#define %26lt;global constant(s)%26gt;
%26lt;global function(s)%26gt;
int main()
{
%26lt;main program%26gt;
}
Reply:You need to clarify what you mean. Are you referring to the comments often seen at the beginning of a source file? Or do you mean actual code? Sorry, but I can't do mind reading, so you will have to add in additional details or repost your question, spelling out exactly what you mean.
I suggest you take a look at popular C and C++ libraries. SGI's STLPort, some of the more well-known libraries on Sourceforge, and so on, are good starting points. Exploring the Linux kernel code will allow you to see how they structure their source files as well.
And for the record, there is no standard format.
Algebra standard form(Ax + By = C)?
does anyone know how to do this algebra problem in standard form? for anyone who answered my last problem, i typed the problem in wrong. anyways, the problem that i cant figure out is y= 9x + 1 over 2.
Algebra standard form(Ax + By = C)?
multiply both sides by 2
2y = 9x + 1
subtract 2y from both sides
0 = 9x - 2y + 1
subtract 1 from both sides
9x -2y = -1
huh. are you sure about the answer?
Algebra standard form(Ax + By = C)?
multiply both sides by 2
2y = 9x + 1
subtract 2y from both sides
0 = 9x - 2y + 1
subtract 1 from both sides
9x -2y = -1
huh. are you sure about the answer?
The standard form for a linear equation is ___. is the answer y=mx+b or Ax+By=C or y=x or x + y = 0 THANKS?
The standard form for a linear equation is ________.
y=mx+b
Ax+By=C
y=x
x + y = 0
The standard form for a linear equation is ___. is the answer y=mx+b or Ax+By=C or y=x or x + y = 0 THANKS?
Ax+By = C
Reply:Ax+By=C
Reply:If you are going to be graphing it, it would be y=my+b. y is the overall line, x is a solution, m is the slope, and b is the y-intercept.
Reply:All of your equations are lines, but you are asking for the "standard form". That is Y=mX+b. This form is ideal for graphing where "m" is the slope, and "b" is the y intercept. We can rearrange all of your other equations above into this format:
Y=X is really Y = 1X + 0 or a slope m=1 and an intercept b=0
X+Y=0 is really Y=-1X+0 or a slope m= -1 and intercept b=0
AX+BY=C is Y=(-A/B)X + (C/B) OR m=-A/B and b = C/B
Best Regards
y=mx+b
Ax+By=C
y=x
x + y = 0
The standard form for a linear equation is ___. is the answer y=mx+b or Ax+By=C or y=x or x + y = 0 THANKS?
Ax+By = C
Reply:Ax+By=C
Reply:If you are going to be graphing it, it would be y=my+b. y is the overall line, x is a solution, m is the slope, and b is the y-intercept.
Reply:All of your equations are lines, but you are asking for the "standard form". That is Y=mX+b. This form is ideal for graphing where "m" is the slope, and "b" is the y intercept. We can rearrange all of your other equations above into this format:
Y=X is really Y = 1X + 0 or a slope m=1 and an intercept b=0
X+Y=0 is really Y=-1X+0 or a slope m= -1 and intercept b=0
AX+BY=C is Y=(-A/B)X + (C/B) OR m=-A/B and b = C/B
Best Regards
Chemistry Calculate the standard entropy change∆ S°that occurs in the following reaction at 25°C and 101.3kpa
Calculate the standard entropy change∆ S°that occurs in the following reaction at 25°C and 101.3kpa
4NH3(g)+7O2(g)--%26gt;4NO2(g)+6H2O(g)
standard entropies S°(J/K X mol)
S° for NH3(g)=192.5
S° for No2(g)=240.5
S° for H2O(g)=188.7
Chemistry Calculate the standard entropy change∆ S°that occurs in the following reaction at 25°C and 101.3kpa
4(S OF NO2)+6(S OF H2O)-4(S OF NH3)=S OF REACTION.
S OF O2 IS 0 AS IT IS AN ELEMENT.
verbena
4NH3(g)+7O2(g)--%26gt;4NO2(g)+6H2O(g)
standard entropies S°(J/K X mol)
S° for NH3(g)=192.5
S° for No2(g)=240.5
S° for H2O(g)=188.7
Chemistry Calculate the standard entropy change∆ S°that occurs in the following reaction at 25°C and 101.3kpa
4(S OF NO2)+6(S OF H2O)-4(S OF NH3)=S OF REACTION.
S OF O2 IS 0 AS IT IS AN ELEMENT.
verbena
If Jesus doesnt exist, why many scientists use B.C. as a standard measure of time?
before Christ?
If Jesus doesnt exist, why many scientists use B.C. as a standard measure of time?
The usual term now is BCE and CE.
(Before Current Era %26amp; Current Era)
Reply:Because it IS the standard measure of time. Many now refer to BCE - before common era, and CE - Common era.
The Julian calendar was the very first time-keeper and it was from this calendar that the Gregorian calendar was formed. The Julian calendar has nothing to do with Jesus and was developed by an astronomer. the Catholic church adapted it to become the Gregorian calendar in 1582 and modified it somewhat by missing 10 days to bring it in line with the seasons. they also added the leap year.
Reply:Many religions have their own calenders starting with the era of the birth of their prophets.
So B.C. calender should be considered as a proof for the existence of Jesus.
For most of the scientific progress took place in west by the scientists who were christians by birth and under the influence of christian rulers, use of B.C. as a measure of time became widely accepted.
Reply:So that everyone will understand what they are talking about. Just because the calendars are based on a mass-delusion doesn't make it any more valid. You could also ask "If the Norse gods don't exist, why do we still use the same names of days of the week?" (Wednesday = Woden's Day, Thursday = Thor's Day, etc.)
Reply:we dont use b.c. genius.
b.c.e.
c.e.
open a book other than the bible please.
Reply:Are you trolling or do you really think this is credible evidence for Jesus? This dating system wasn't adopted until hundreds of years post the origin of Christianity and only shows that the belief had become widespread. It doesn't prove the existence of the individual. In fact, there are controversies that the start year doesn't jibe with calculations of when Jesus might have been born trying to derive it from written sources. No one can pinpoint it since there is no proof. Many think dating it from events in the Bible and trying to match them with real events recorded elsewhere indicate it could have been 4 B.C.. but no one really knows or if there is any real birthdate to begin with.
Reply:actually we use BCE (before common era)
ore BP (Before Present) - in this case 'present' is considered to be nineteen fifty something....like 1953-4....i forget exact year.
Reply:they should switch to B.C.E. (before common era)
Reply:because it is a widely known and used standard, also christians have a hate thing about the use of bce and ace
Reply:Because Christianity exists. Why do we call the fifth day of the week "Thursday" (Thorsdaeg) if Thor doesn't exist? What about Wednesday if Woden (Odin) doesn't exist?
I'll admit to the existence of Jesus if you admit to the existence of Thor and Odin. Sound fair?
Reply:Ever notice for an atheist , Half Ape Half god wastes a lot of time of his apparent precious life on this site?
Reply:Because it's a societal convention. And early Christianity spread religion by blood and fire (crusades, inquisition, witch trials, etc.) so they took over Western society, and the dating methods used became standardised worldwide, although these days more and more people are using BCE and CE (Before Common Era and Common Era) as a less religious way of dating.
If Christians don't believe in Norse mythology, why do they keep referring to Wednesday, Thursday and Friday? (Woden's day, Thor's day and Freya's day) Same deal really.
Reply:it can also stand for Before computers
Reply:because its an accepted measure of time and they also use bce (but i cant remember what it stands for) and also just because we say its winter doesnt mean its snowing
Reply:Because if they didn't, our whole system of time and records of events etc would have to be altered. Re-writing two thousand years of history being recorded in this manner would be a collossal task, for very little benefit.
Reply:Tell you a little secret
BCE = Before Christian era
CE = Christian Era
God of Providence confounded them eh??
HalleluYAH!
If Jesus doesnt exist, why many scientists use B.C. as a standard measure of time?
The usual term now is BCE and CE.
(Before Current Era %26amp; Current Era)
Reply:Because it IS the standard measure of time. Many now refer to BCE - before common era, and CE - Common era.
The Julian calendar was the very first time-keeper and it was from this calendar that the Gregorian calendar was formed. The Julian calendar has nothing to do with Jesus and was developed by an astronomer. the Catholic church adapted it to become the Gregorian calendar in 1582 and modified it somewhat by missing 10 days to bring it in line with the seasons. they also added the leap year.
Reply:Many religions have their own calenders starting with the era of the birth of their prophets.
So B.C. calender should be considered as a proof for the existence of Jesus.
For most of the scientific progress took place in west by the scientists who were christians by birth and under the influence of christian rulers, use of B.C. as a measure of time became widely accepted.
Reply:So that everyone will understand what they are talking about. Just because the calendars are based on a mass-delusion doesn't make it any more valid. You could also ask "If the Norse gods don't exist, why do we still use the same names of days of the week?" (Wednesday = Woden's Day, Thursday = Thor's Day, etc.)
Reply:we dont use b.c. genius.
b.c.e.
c.e.
open a book other than the bible please.
Reply:Are you trolling or do you really think this is credible evidence for Jesus? This dating system wasn't adopted until hundreds of years post the origin of Christianity and only shows that the belief had become widespread. It doesn't prove the existence of the individual. In fact, there are controversies that the start year doesn't jibe with calculations of when Jesus might have been born trying to derive it from written sources. No one can pinpoint it since there is no proof. Many think dating it from events in the Bible and trying to match them with real events recorded elsewhere indicate it could have been 4 B.C.. but no one really knows or if there is any real birthdate to begin with.
Reply:actually we use BCE (before common era)
ore BP (Before Present) - in this case 'present' is considered to be nineteen fifty something....like 1953-4....i forget exact year.
Reply:they should switch to B.C.E. (before common era)
Reply:because it is a widely known and used standard, also christians have a hate thing about the use of bce and ace
Reply:Because Christianity exists. Why do we call the fifth day of the week "Thursday" (Thorsdaeg) if Thor doesn't exist? What about Wednesday if Woden (Odin) doesn't exist?
I'll admit to the existence of Jesus if you admit to the existence of Thor and Odin. Sound fair?
Reply:Ever notice for an atheist , Half Ape Half god wastes a lot of time of his apparent precious life on this site?
Reply:Because it's a societal convention. And early Christianity spread religion by blood and fire (crusades, inquisition, witch trials, etc.) so they took over Western society, and the dating methods used became standardised worldwide, although these days more and more people are using BCE and CE (Before Common Era and Common Era) as a less religious way of dating.
If Christians don't believe in Norse mythology, why do they keep referring to Wednesday, Thursday and Friday? (Woden's day, Thor's day and Freya's day) Same deal really.
Reply:it can also stand for Before computers
Reply:because its an accepted measure of time and they also use bce (but i cant remember what it stands for) and also just because we say its winter doesnt mean its snowing
Reply:Because if they didn't, our whole system of time and records of events etc would have to be altered. Re-writing two thousand years of history being recorded in this manner would be a collossal task, for very little benefit.
Reply:Tell you a little secret
BCE = Before Christian era
CE = Christian Era
God of Providence confounded them eh??
HalleluYAH!
Calculate the standard entropy change for the combustion of methanol at 25 °C.?
Calculate the standard entropy change for the combustion of methanol at 25 °C.
2 CH3OH(λ) + 3 O2(g) → 2 CO2(g) + 4 H2O(g)
Species S° (J/K⋅mol)
CH 3 OH (λ) 127.2
O 2 (g) 205.1
CO 2 (g) 213.7
H 2 O(g) 188.8
a.-312.9 J/K
b.+70.2 J/K
c.+2052.3 J/K
d.-2052.3 J/K
e.+312.9 J/K
Calculate the standard entropy change for the combustion of methanol at 25 °C.?
DeltaS = DeltaS(Products) - DeltaS(Reactants).
DeltaS = [2(213.7) + 4(188.8)] - [ 2(127.2) + 3(205.1)]
DeltaS = [427.4 + 755.2] - [254.4 + 615.3]
DeltaS = 1182.6 - 869.7
DeltaS = 312.9 JK^-1
'e' is the correct answer.
2 CH3OH(λ) + 3 O2(g) → 2 CO2(g) + 4 H2O(g)
Species S° (J/K⋅mol)
CH 3 OH (λ) 127.2
O 2 (g) 205.1
CO 2 (g) 213.7
H 2 O(g) 188.8
a.-312.9 J/K
b.+70.2 J/K
c.+2052.3 J/K
d.-2052.3 J/K
e.+312.9 J/K
Calculate the standard entropy change for the combustion of methanol at 25 °C.?
DeltaS = DeltaS(Products) - DeltaS(Reactants).
DeltaS = [2(213.7) + 4(188.8)] - [ 2(127.2) + 3(205.1)]
DeltaS = [427.4 + 755.2] - [254.4 + 615.3]
DeltaS = 1182.6 - 869.7
DeltaS = 312.9 JK^-1
'e' is the correct answer.
Standard enthalpy of formation for acetic acid at 25 degrees C?
standard heat of combustion of acetic acid is -874.5kjmol^-1
dHf for:
Co2: -393.5
C: 0
H2: 0
H2O: -285.83
CO2:0
CH3COOH: ?
all values taken at 298K= 25degrees C
CH3COOh+2O2= 2CO2+2H2O
Standard enthalpy of formation for acetic acid at 25 degrees C?
1 CH3COOH + 2 O2 --%26gt; 2 CO2 + 2 H2O
-874.5 kJ = prod - reactants
-874.5 kJ = ( 2 CO2 %26amp; 2 H2O) - (1 CH3COOH %26amp; 2 O2)
-874.5 kJ = ( -787.0 %26amp; -571.66) - (1 CH3COOH %26amp; zero)
-874.5 kJ = (-1358.66) - ( CH3COOH)
-874.5 kJ + 1358.66 = - ( CH3COOH)
484.16 = - ( CH3COOH)
ANSWER CH3COOH = - 484.2 kilojoules
vs Std enthalpy of formation liquid −483.5 kJ/mol
dHf for:
Co2: -393.5
C: 0
H2: 0
H2O: -285.83
CO2:0
CH3COOH: ?
all values taken at 298K= 25degrees C
CH3COOh+2O2= 2CO2+2H2O
Standard enthalpy of formation for acetic acid at 25 degrees C?
1 CH3COOH + 2 O2 --%26gt; 2 CO2 + 2 H2O
-874.5 kJ = prod - reactants
-874.5 kJ = ( 2 CO2 %26amp; 2 H2O) - (1 CH3COOH %26amp; 2 O2)
-874.5 kJ = ( -787.0 %26amp; -571.66) - (1 CH3COOH %26amp; zero)
-874.5 kJ = (-1358.66) - ( CH3COOH)
-874.5 kJ + 1358.66 = - ( CH3COOH)
484.16 = - ( CH3COOH)
ANSWER CH3COOH = - 484.2 kilojoules
vs Std enthalpy of formation liquid −483.5 kJ/mol
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