Calculate the standard entropy change for the combustion of methanol at 25 °C.?

Calculate the standard entropy change for the combustion of methanol at 25 °C.





2 CH3OH(λ) + 3 O2(g) → 2 CO2(g) + 4 H2O(g)





Species S° (J/K⋅mol)


CH 3 OH (λ) 127.2


O 2 (g) 205.1


CO 2 (g) 213.7


H 2 O(g) 188.8





a.-312.9 J/K


b.+70.2 J/K


c.+2052.3 J/K


d.-2052.3 J/K


e.+312.9 J/K

Calculate the standard entropy change for the combustion of methanol at 25 °C.?
DeltaS = DeltaS(Products) - DeltaS(Reactants).


DeltaS = [2(213.7) + 4(188.8)] - [ 2(127.2) + 3(205.1)]


DeltaS = [427.4 + 755.2] - [254.4 + 615.3]


DeltaS = 1182.6 - 869.7


DeltaS = 312.9 JK^-1





'e' is the correct answer.