What is y=3/4x + 3 in standard form [ax+by=C]?

i Just need the answer but it would be kind to explain how you got it..





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What is y=3/4x + 3 in standard form [ax+by=C]?
y = 3/2x + 3 (times both sides by 2)





2y = 3x + 6 (subtract both sides by 3x)





-3x + 2y = 6 and there you have it, it's in standard form!
Reply:Assume question is:-


y = (3/2) x + 3


2y = 3x + 6


3x - 2y = - 6
Reply:y= (3/2) x + 3


(Moving (3/2) x to the left side)


-(3/2) x + y = 3


(Comparing with ax + by = c)





Answer = a= -3/2; b= 1, c=3.


Simple.
Reply:All you need to do is move the x and y to the same side of the equation.





y = (3/2)x + 3





Subtract (3/2)x from both sides, because you have to do the same thing to both sides of the equation, and you get:





-(3/2)x + y = 3





A= -(3/2)


B= 1


C= 3
Reply:y = 3/4x + 3


4/3(3/4x - y) = 4/3(- 3)


x - 4/3y = - 4
Reply:y = 3/2x + 3


first clear the fraction by multiplying all three terms by the denominator 2





2y = 3x + 6





subtract 3x over to left side





-3x + 2y = 6





normally it is preferred to have the x term positive, so multiply through the equation by -1





3x - 2y = -6