Write the equatin of the line in standard form (Ax+By=C) that passes through points: (-5,10) and (-4,-2).?

Any line with the equation y=mx+c has a slope of m and a y-intercept of c.





You know that when x=-5, y=10, so if you plug these into your y=mx+c formula:





10=-5m+c





You also know that when x=-4 y=-2, so if you plug these into your y=mx+c formula:





-2=-4m+c





You can now solve these as simultaneous equations:





Let equation 1 be 10=-5m+c


Let equation 2 be -2=-4m+c





Take equation 2 from equation 1:


12=-m


so m=-12





Plug this value into equation 1:


10=(-5*-12)+c


10=60+c


so c=-50





Therefore your y=mx+c equation is:


y=-12x-50





Rewriting for the form Ax+By=c:


12x+y=-50

Write the equatin of the line in standard form (Ax+By=C) that passes through points: (-5,10) and (-4,-2).?
first get the slope:


(-2 - 10) / (-4 - (-5) ) = -12/1 = -12


then use point-slope formula:


y - y1 = m(x - x1)





y - 10 = -12(x - (-5))





y - 10 = -12(x + 5)





y - 10 = -12x - 60





y = -12x - 50





12x + y = -50
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