How do you convert two points to standard form(ax+by=c)?

to be more specific, the points are A(6, -1) and B (-3, 7).

How do you convert two points to standard form(ax+by=c)?
1st: compute the slope(m) of the line passing through those points.





2nd: substitute the slope into the point-slope form of the equation of a line: (x-x1)=m(y-y1).





3rd: rearrange into the standard form
Reply:First get y on the LHS:


by = -ax + c


y(x) = (-a/b)x + c/b = mx + d


y(6) = m(6) + d = -1


y(-3) = m(-3) + d = 7


Subtract the second from the first:


9m = -8


m = -8/9 = -a/b by the eqn for y(x) above


(-8/9)(-3) + d = 7


8/3 + d = 7


d = 7 - 8/3 = 21/3 - 8/3 = 13/3 = c/b from above


a = 8, b = 9, c = 13/3 (3/3)b = 39/9 b, so c = 39


8x + 9y = 39 is the answer
Reply:y-(-1)/x-6 = 7-(-1)/-3-6


y+1/x-6 = 7+1/-9


-9(y+1) = 8(x-6)


-9y-9 = 8x-48


8x+9y = 48-9


8x+9y = 39


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