How do i do this algebra problem in standard form(Ax + By = C)?

how do i do this algebra problem in standard form?





y= 9x + 1

How do i do this algebra problem in standard form(Ax + By = C)?
y-9x=1


-9x+y=1
Reply:You have to get the X and the y on the same side, so, subtract 9x


from each side:


y= 9x + 1


So now you have: -9x +y =1


Its in standard from now.


.
Reply:Just move stuff around by doing the same thing to both sides of the equation:





First, subtract one y from each side:





0 = 9x - y + 1





Then subtract 1 from each side:





-1 = 9x - y





Then you can flip it if you want:





9x - y = -1





And:





A = 9


B = -1


C = -1
Reply:y=9x+1


y-9x=9x-9x+1


-9x+y=1





9x-y=-1, in which a=9, b=-1, and c=-1
Reply:In standard form "A" cannot be negative, so y=9x+1 becomes:





9x -y = -1





that's it! ;)
Reply::] ok





first you subsitute y= 9x+1 into Ax+By= C





you get Ax+B(9x+1)=C





distribute Ax+9B+B=C





put in standard form x(A+9B)+B=C





simplify x= C-B/ A+9B

cabbage