C(graphite) + 2 Cl2(g) CCl4(l)
2.Calculate the value of the thermodynamic equilibrium constant K.
What is the standard free-energy change G° at 25°C for the following reaction?
Lancenigo di Villorba (TV), Italy
The reaction involved is
C(Graphite) + 2 Cl2(g) ---%26gt; CCl4(l)
Its own STANDARD GIBB-FREE ENERGY's CHANGE follows
DeltaG° = (G°f,CCl4) - (G°f,C + 2 * G°f,Cl2) =
= (-203,344) - (0.0 + 2 * 0.0) = -203,344 J/mol
Instead I use the FORMATION's GIBB-FREE ENERGY for Carbon Tetrachloride, I assumed NIHIL the other ones since they refer to MOST STABLE ALLOTROPIC STATES of Chemical Elements.
The "Isothermal van't Hoff Equation"
DeltaG = DeltaG° + R * T * SUM[nu,i * LN(a,i)]
may be rearranged at the Equilibrium Conditions, e.g. where it is DeltaG = 0 and SUM[nu,i * LN(a,i)] = LN(Keq)
so it is
Keq = EXP(0 - DeltaG° / (R * T)) =
= EXP(0 - (-203,344) / (8.3 * 298.16)) = 4.8E+35
I hope this could be clear.
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