How do u write the line that passes thporugh (4,-2) and (2,-4) in standard ax+by=c form without switching vari

ables during ur work

How do u write the line that passes thporugh (4,-2) and (2,-4) in standard ax+by=c form without switching vari
First, you need to calculate the slope:


change in y = -4 - -2 = -2


change in x = 2 - 4 = -2


Thus the slope = -2 / -2 = 1





Using the point slope equation of a line (and either point, I'll use the first point), the equation of the line is:


y - -2 = 1 (x - 4), so


y+2 = x-4, and collecting terms


x - y = 6





Now we check the two points are on this line:


4 - -2 = 6 yes!


2 - -4 = 6 yes!
Reply:y = (ax + c)/b where your slope = a/b and your y-int = c/b





slope = rise/run = -2/-2; therefore a = -2 = b





pick a point, say (4, -2) and plug in for x and y, and solve for c, the only variable you have left to solve for yielding





x - y- 6 =0
Reply:slope,m=2/2=1


EQ is


y+2=1(x-4).


x-y-6=0
Reply:First in order to write the line that passes through the points given you have to find the slope. You can find slope by the formula y2-y1/x2-x1 which = 1


x-y=6


check 4--2=6


check 2--4=6





They both check out





Best of luck